Mathematics
Easy

Question

# Solve the system:y = -2x + 202x + y = 20

## No solution(11, 8)(5, 15)Infinitely many solutions. Hint:

## The correct answer is: Infinitely many solutions.

### Here we have to find the system of equation.Firstly, we have given equation y = -2x + 20 and 2x + y = 20.So , y = -2x + 20      --(1)2x + y = 20       --(2)We have a1 = 2 , b1 = 1 and c1 = 20And a2 = 2 , b2 = 1 and c2 = 20,Now , a1/a2 = 2/2 =1 ,b1/b2 = 1and c1/ c2 = 20/20 = 1Therefore, a1/a2 = b1/b2 = c1/c2So, it solution having infinitely many solution.The correct answer is Infinitely many solution.Or Another way to solve the question,y = -2x + 20 …(i)2x + y = 20 …(ii)Substituting y from (i) in (ii), we get 2x + (-2x + 20) = 2020 = 20The statement 20 = 20 is an identity, so the system of equations has infinitely many solutions

In this question, we have solve this question by system of equation we have , if (a1/a2) = (b1/b2) = (c1/c2) then it is infinitely many solutions, if  (a1/a2) = (b1/b2) ≠ (c1/c2) and if (a1/a2) ≠(b1/b2) then it is unique solution.

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