Mathematics
Grade10
Easy
Question
Solve the system:
Y = -x + 10
x + y = 5
- No solution
- (11, 8)
- (5, 15)
- Infinitely many solutions.
Hint:
In this question, we are given two system of equation , we have to find the value x and y. Make two equation , if (a1/a2) = (b1/b2) = (c1/c2) then it is infinitely many solutions, if (a1/a2) = (b1/b2) ≠ (c1/c2) and if (a1/a2) ≠(b1/b2) then it is unique solution.
The correct answer is: No solution
Here we have solve the system of equation and find x and y.
Firstly , we are given, y = -x + 10 and x + y = 5
So we can write,
x + y =10 -------( 1)
x + y = 5 --------(2)
Now , we have a1/a2
a1/a2 = 1/1 =1
and b1/b2 ,
b1/b2 = 1/1 = 1
and c1/c2
c1/c2 = 10/5 = 2
so here,
1 = 1 ≠ 2
a1/a2 = b1/b2 ≠ c1/c2
Therefore, the system of equation of no solution.
The correct answer is No solution.
Or, another way to solve question,
y = -x + 10 …(i)
x + y = 5 …(ii)
Substituting y from (i) in (ii), we get
x + (-x + 10) = 5
10 = 5
The statement 10 = 5 is false, so the system of equations has no solution.
In this question, we have to find the system of equation. If (a1/a2) = (b1/b2) = (c1/c2) then it is infinitely many solutions, if (a1/a2) = (b1/b2) ≠ (c1/c2) and if (a1/a2) ≠(b1/b2) then it is unique solution.