Question
The coordinates of the vertex of the parabola whose equation is are:
- (2, 11)
- (-1, -7)
- (1, 1)
- (-2, -6)
Hint:
In this question, we have to find the k value of vertex (h, k) for the equation . Vertex form is another form of a quadratic equation. The standard form of a quadratic equation is a + bx + c. The vertex form of a quadratic equation is a + k where a is a constant that tells us whether the parabola opens upwards or downwards, and (h, k) is the location of the vertex of the parabola.
The correct answer is: (-2, -6)
Given quadratic equation,
Now we isolate constants to the other side,
Adding 4 on both sides, we get
The vertex form of the quadratic equation is .
Therefore, vertex is (-2, -6).
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The other method to find the vertex of a parabola is as we know that the x-coordinate of a vertex, (i.e) h is -b/2a.Now, substitute the x-coordinate value in the given standard form of the parabola equation y=ax2+bx+c, we will get the y-coordinate of a vertex.
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The coordinates of the vertex of the parabola, whose equation is y = 2x2 + 4x - 5 are:
The other method to find the vertex of a parabola is as We know that the x-coordinate of a vertex, (i.e) h is -b/2a. Now, substitute the x-coordinate value in the given standard form of the parabola equation y=ax2+bx+c, we will get the y-coordinate of a vertex.
The coordinates of the vertex of the parabola, whose equation is y = 2x2 + 4x - 5 are:
The other method to find the vertex of a parabola is as We know that the x-coordinate of a vertex, (i.e) h is -b/2a. Now, substitute the x-coordinate value in the given standard form of the parabola equation y=ax2+bx+c, we will get the y-coordinate of a vertex.