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    Mathematics
    Grade10
    Easy

    Question

    The first term of the sequence a subscript 3 end subscript equals 8 open parentheses fraction numerator 1 over denominator 2 end fraction close parentheses to the power of 7 end exponent is _______.

    1. 3    
    2. 7    
    3. fraction numerator 1 over denominator 2 end fraction    
    4. 8    

    hintHint:

    In a geometric progression, each successive term is obtained by multiplying the common ratio to its
    preceding term. The formula for the nth term of a geometric progression whose first term is a and
    common ratio is r is: an=arn-1.

    The correct answer is: 8

      Give that; sequence a subscript 3 end subscript equals 8 open parentheses fraction numerator 1 over denominator 2 end fraction close parentheses to the power of 7 end exponent
      In a geometric progression, each successive term is obtained by multiplying the common ratio to its
      preceding term. The formula for the nth term of a geometric progression whose first term is a and
      common ratio is r is: an=arn-1.
      Therefore; The first term of the sequence is 8.

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