Mathematics
Grade6
Easy
Question
The product of two fractions is 15. If one of the fractions is
, find the other fraction?
Hint:
If the product of two fractions is given and one of the fractions is known the to find the unknown fraction
divide product of two fractions by one of the known fractions.
The correct answer is: ![fraction numerator 9 over denominator 2 end fraction](data:image/png;base64,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)
The product of two fractions is 15.
Convert mixed fraction to improper fraction using
Improper fraction = ![fraction numerator open parentheses text Whole number × Denominator end text close parentheses text + Numerator end text over denominator text Denominator end text end fraction](https://lh5.googleusercontent.com/uT2qxo8dAB_VSIa-rISP0G8h0QDDTt2S55Ta-JNFUJUJVcxwC9amcQzPCSvEprCXVZIyCSwZuaxvFcrvvpCPEGeq9htCIRl3P6OD0p6TTig6BWBA126QOu-lieVHxBhUGayon7SCNnwd-PPHxDsUtN0)
One of the fractions is
.
The required fraction is ![15 divided by fraction numerator 10 over denominator 3 end fraction](data:image/png;base64,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)
we can multiply the reciprocal of the denominator with the numerator to find the value of the problem.
.
Therefore, the unknown fraction is
.
Therefore, the unknown fraction is