Mathematics
Grade6
Easy

Question

The product of two fractions is 15. If one of the fractions is 3 fraction numerator 1 over denominator 3 end fraction, find the other fraction?

  1. fraction numerator 5 over denominator 2 end fraction    
  2. fraction numerator 9 over denominator 2 end fraction    
  3. fraction numerator 3 over denominator 2 end fraction    
  4. fraction numerator 7 over denominator 2 end fraction    

Hint:

If the product of two fractions is given and one of the fractions is known the to find the unknown fraction
divide product of two fractions by one of the known fractions.

The correct answer is: fraction numerator 9 over denominator 2 end fraction


    The product of two fractions is 15.
    Convert mixed fraction to improper fraction using
    Improper fraction = fraction numerator open parentheses text Whole number × Denominator end text close parentheses text  + Numerator end text over denominator text Denominator end text end fraction
    One of the fractions is 3 1 third equals fraction numerator left parenthesis 3 cross times 3 right parenthesis plus 1 over denominator 3 end fraction equals 10 over 3.
    The required fraction is 15 divided by fraction numerator 10 over denominator 3 end fraction

    we can multiply the reciprocal of the denominator with the numerator to find the value of the problem.
    equals 15 cross times 3 over 10 left parenthesis space R e c i p r o c a l space o f space 10 over 3 space i s space 3 over 10 right parenthesis equals 9 over 2.
    Therefore, the unknown fraction is 9 over 2.

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