Mathematics
Grade6
Easy

Question

. The product of two fractions is 2 fraction numerator 1 over denominator 4 end fraction. If one of the fractions is 1 fraction numerator 1 over denominator 4 end fraction, then find the other number.

  1. 1 fraction numerator 1 over denominator 5 end fraction    
  2. 1 fraction numerator 4 over denominator 5 end fraction    
  3. 2 fraction numerator 4 over denominator 5 end fraction    
  4. 2 fraction numerator 1 over denominator 5 end fraction    

hintHint:

if the product of two fractions and one of the fraction is known , to find the other fraction we divide product by known fraction . To simplify convert the mixed fractions to improper fractions.

The correct answer is: 1 fraction numerator 4 over denominator 5 end fraction


    Mixed fraction to Improper fraction = fraction numerator open parentheses text Whole number × Denominator end text close parentheses text  + Numerator end text over denominator text Denominator end text end fraction
    The product of fractions = 2 1 fourth equals space fraction numerator left parenthesis 2 cross times 4 right parenthesis plus 1 over denominator 4 end fraction space equals space 9 over 4
    One of the fractions is 1 1 fourth space equals fraction numerator left parenthesis 4 cross times 1 right parenthesis plus 1 over denominator 4 end fraction equals 5 over 4
    therefore The required fraction is equals fraction numerator 9 over denominator 4 end fraction divided by fraction numerator 5 over denominator 4 end fraction
    we can multiply the reciprocal of the denominator with the numerator to find the value of the problem.
    equals fraction numerator 9 over denominator 4 end fraction cross times fraction numerator 4 over denominator 5 end fraction equals fraction numerator 9 over denominator 5 end fraction equals 1 fraction numerator 4 over denominator 5 end fraction.
    Therefore, the unknown fraction is 1 4 over 5.

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