Mathematics
Grade10
Easy
Question
The ratio of incomes of two persons is 9:7, and the ratio of their expenditure is 4:3. If each of them manages to save $2000 per month, find their monthly expenditure?
- $16000, $12000
- $8000, $10000
- $11000, $20000
- None of the above
Hint:
An equation with the maximum order of 1 and an equation of a straight line is called the linear equation.
The correct answer is: $16000, $12000
Step 1 of 1:
We have given the ratio of incomes of two persons is 9:7, and the ratio of their expenditure is 4:3. If each of them manages to save $2000 per month
Let the income be x and expenditure be y
Saving per month = $2000
Then
9x – 4y = 2000………………….. 1
7x – 3y = 2000……………… 2
From 1
9x – 4y = 2000
9x = 2000 + 4y
x = ![fraction numerator 2000 plus 4 y over denominator 9 end fraction](data:image/png;base64,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)
Substituting x in 2nd equation,
7
- 3y = 2000
- 3y = 2000
14000+ 28y – 27y = 18000
14000 + 1y = 18000
y = 4000
4y = 4 x 4000
=16000
3y = 3 x 4000
= 12000
The substitution method is the algebraic method to solve simultaneous linear equations.