Mathematics
Grade6
Easy

Question

The relationship between speed(s), distance(d) and time(t) is given by s = fraction numerator d over denominator t end fraction. Find the value of s, d = 135 m and t =10 m

  1. fraction numerator 27 over denominator 2 end fraction fraction numerator m over denominator s end fraction    
  2. fraction numerator 50 over denominator 2 end fraction fraction numerator m over denominator s end fraction    
  3. fraction numerator 24 over denominator 5 end fraction fraction numerator m over denominator s end fraction    
  4. None of the above    

Hint:

The given expression for speed is an algebraic expression. It has three variables: distance ‘d’ , time ‘t’ and speed ‘s’. They are related to each other by an algebraic operation. The value of speed is equal to division of distance ‘d’ by time ‘t’. In this question, value is assigned to the variables. We have to perform the required operations and find the final value.

The correct answer is: fraction numerator 27 over denominator 2 end fraction fraction numerator m over denominator s end fraction


    The given expression is s space equals d over t 
        There are three variables here. The values of two variables are given. We have to use the relation between them and find the third value.
    The values of variables is as follows:
    d = 135m
    t = 10s
    We have to substitute these values in the above expression and we will get the value of ‘s’.
    To substitute the values we will replace the variables by their respective values.
    So we get
    s space equals space d over t
s space equals space fraction numerator 135 space over denominator 10 end fraction m over s
s space equals space 27 over 2 m over s
    Therefore, the value of speed is 27 over 2 m over s .
       So option (a) is the right option.

    We have to be careful about the operations because of the variables. We have to follow the proper procedure for performing the operations. The variables take different values under different conditions. So we have to be careful while substituting the values. The main part of this type of question is just replacing the variables by their values and performing the operation.

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