Mathematics
Grade-7
Easy

Question

The sum or difference of  negative 13 over 12 minus open parentheses fraction numerator negative 8 over denominator 12 end fraction close parentheses  is _____________.

  1. 11 over 12
  2. fraction numerator negative 11 over denominator 12 end fraction
  3. fraction numerator negative 5 over denominator 12 end fraction
  4. fraction numerator negative 2 over denominator 15 end fraction

The correct answer is: fraction numerator negative 5 over denominator 12 end fraction


    STEP BY STEP SOLUTION
    fraction numerator negative 13 over denominator 12 end fraction space plus space 8 over 12
T a k i n g space t h e space L C M thin space o f space t h e space a b o v e space t w o space f r a c t i o n space
fraction numerator negative 13 space plus space 8 over denominator 12 end fraction
N o w space s i m p l i f y i n g space t h e space q u e s t i o n space
fraction numerator negative 5 over denominator 12 end fraction
    The answer of the above question is fraction numerator negative 5 over denominator 12 end fraction or -0.41

    Related Questions to study

    Grade-7
    Mathematics

    The value of  2 left parenthesis 0.6 right parenthesis space plus space open parentheses fraction numerator negative 1 over denominator 9 end fraction close parentheses is ___________.

    STEP BY STEP SOLUTION
    2 left parenthesis 0.6 right parenthesis space plus space open parentheses negative 1 over 9 close parentheses space
C o n v e r t i n g space d e c i m a l space i n t o space f r a c t i o n space
equals space 2 space cross times space 6 over 10 space plus space open parentheses negative 1 over 9 close parentheses space
M u l t i p l y i n g space a n d space o p e n i n g space b r a c k e t space
equals space 12 over 10 space minus space 1 over 9 space
T a k i n g space L C M thin space o f space 10 space & space 9 space left parenthesis i. e space 90 right parenthesis
fraction numerator 108 space minus space 10 space over denominator 90 end fraction space equals fraction numerator space 98 over denominator 90 end fraction space equals space 49 over 45

    The value of  2 left parenthesis 0.6 right parenthesis space plus space open parentheses fraction numerator negative 1 over denominator 9 end fraction close parentheses is ___________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    2 left parenthesis 0.6 right parenthesis space plus space open parentheses negative 1 over 9 close parentheses space
C o n v e r t i n g space d e c i m a l space i n t o space f r a c t i o n space
equals space 2 space cross times space 6 over 10 space plus space open parentheses negative 1 over 9 close parentheses space
M u l t i p l y i n g space a n d space o p e n i n g space b r a c k e t space
equals space 12 over 10 space minus space 1 over 9 space
T a k i n g space L C M thin space o f space 10 space & space 9 space left parenthesis i. e space 90 right parenthesis
fraction numerator 108 space minus space 10 space over denominator 90 end fraction space equals fraction numerator space 98 over denominator 90 end fraction space equals space 49 over 45
    Grade-7
    Mathematics

    The sum or difference of  negative 2 over 3 plus 4 over 3 is __________.

    STEP  BY STEP SOLUTION
    negative 2 over 3 plus space 4 over 3
T a k i n g space L C M thin space
fraction numerator negative 2 plus 4 over denominator 3 end fraction space equals space 2 over 3
    The answerof this question is 2 over 3

    The sum or difference of  negative 2 over 3 plus 4 over 3 is __________.

    MathematicsGrade-7
    STEP  BY STEP SOLUTION
    negative 2 over 3 plus space 4 over 3
T a k i n g space L C M thin space
fraction numerator negative 2 plus 4 over denominator 3 end fraction space equals space 2 over 3
    The answerof this question is 2 over 3
    Grade-7
    Mathematics

    Simplify 2 open parentheses negative 1 third close parentheses space plus space 3 open parentheses negative 1 fourth close parentheses space plus space 1 open parentheses fraction numerator negative 1 over denominator 2 end fraction close parentheses

    STEP BY STEP SOLUTION
    2 open parentheses negative 1 third close parentheses space plus space 3 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses space plus space 1 open parentheses fraction numerator negative 1 over denominator 2 end fraction close parentheses space
O p e n i n g space b r a c k e t s space a n d space m u l t i p l y i n g space
equals space fraction numerator negative 2 over denominator 3 end fraction space minus space 3 over 4 space minus space 1 half
T a k i n g space L C M space o f space 3 comma 4 & 2 space left parenthesis i. e space 12 right parenthesis
space equals space fraction numerator negative 8 space minus space 9 space minus space 6 over denominator 12 end fraction space equals space fraction numerator negative 23 over denominator 12 end fraction

    Simplify 2 open parentheses negative 1 third close parentheses space plus space 3 open parentheses negative 1 fourth close parentheses space plus space 1 open parentheses fraction numerator negative 1 over denominator 2 end fraction close parentheses

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    2 open parentheses negative 1 third close parentheses space plus space 3 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses space plus space 1 open parentheses fraction numerator negative 1 over denominator 2 end fraction close parentheses space
O p e n i n g space b r a c k e t s space a n d space m u l t i p l y i n g space
equals space fraction numerator negative 2 over denominator 3 end fraction space minus space 3 over 4 space minus space 1 half
T a k i n g space L C M space o f space 3 comma 4 & 2 space left parenthesis i. e space 12 right parenthesis
space equals space fraction numerator negative 8 space minus space 9 space minus space 6 over denominator 12 end fraction space equals space fraction numerator negative 23 over denominator 12 end fraction
    parallel
    Grade-7
    Mathematics

    The sum or difference of negative 5.5 minus open parentheses negative 3 1 half close parentheses is _________.

    STEP BY STEP SOLUTION
    negative 5.5 minus open parentheses negative 3 1 half close parentheses
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals negative 5.5 space minus space open parentheses negative 7 over 2 close parentheses
O p e n i n g space b r a c k e t space
equals space minus 5.5 space plus 7 over 2
C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l space o r space t a k i n g space L C M space
equals negative 5.5 plus 3.5 equals negative 2.0
T h e space a n s w e r space o f space a b o v e space q u e s t i o n space i s space minus 2.0

    The sum or difference of negative 5.5 minus open parentheses negative 3 1 half close parentheses is _________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    negative 5.5 minus open parentheses negative 3 1 half close parentheses
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals negative 5.5 space minus space open parentheses negative 7 over 2 close parentheses
O p e n i n g space b r a c k e t space
equals space minus 5.5 space plus 7 over 2
C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l space o r space t a k i n g space L C M space
equals negative 5.5 plus 3.5 equals negative 2.0
T h e space a n s w e r space o f space a b o v e space q u e s t i o n space i s space minus 2.0
    Grade-7
    Mathematics

    The value of  2 open parentheses negative 4 over 3 close parentheses space divided by space 2 open parentheses negative 6 over 9 close parentheses is _________.

    STEP BY STEP SOLUTION
    2 open parentheses fraction numerator negative 4 over denominator 3 end fraction close parentheses space minus space 2 open parentheses fraction numerator negative 6 over denominator 9 end fraction close parentheses space
M u l t i p l y i n g space 2 space a n d space o p e n i n g space b r a c k e t
equals space minus 8 over 3 space plus 12 over 9 space
T a k i n g space L C M thin space o f space 3 & 9 space left parenthesis i. e space 9 right parenthesis
equals space fraction numerator negative 24 space plus 12 over denominator 9 end fraction space
equals negative space 12 over 9 space equals negative space fraction numerator 4 over denominator space 3 end fraction

    The value of  2 open parentheses negative 4 over 3 close parentheses space divided by space 2 open parentheses negative 6 over 9 close parentheses is _________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    2 open parentheses fraction numerator negative 4 over denominator 3 end fraction close parentheses space minus space 2 open parentheses fraction numerator negative 6 over denominator 9 end fraction close parentheses space
M u l t i p l y i n g space 2 space a n d space o p e n i n g space b r a c k e t
equals space minus 8 over 3 space plus 12 over 9 space
T a k i n g space L C M thin space o f space 3 & 9 space left parenthesis i. e space 9 right parenthesis
equals space fraction numerator negative 24 space plus 12 over denominator 9 end fraction space
equals negative space 12 over 9 space equals negative space fraction numerator 4 over denominator space 3 end fraction
    Grade-7
    Mathematics

    Determine the distance between 2.5 and - 0.5 on the number line shown

    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    So, we will subract -0.5 from 2.5
    |2.5 – (-0.5) | = |2.5 + 0.5| = 3 units.

    Determine the distance between 2.5 and - 0.5 on the number line shown

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    So, we will subract -0.5 from 2.5
    |2.5 – (-0.5) | = |2.5 + 0.5| = 3 units.
    parallel
    Grade-7
    Mathematics

    The distance between the numbers -4 and 2 on the number line is _____.

    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    open vertical bar negative 4 minus 2 close vertical bar
open vertical bar negative 6 close vertical bar
6

    So, the distance between -4 and 2 is 6 units 

    The distance between the numbers -4 and 2 on the number line is _____.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    open vertical bar negative 4 minus 2 close vertical bar
open vertical bar negative 6 close vertical bar
6

    So, the distance between -4 and 2 is 6 units 

    Grade-7
    Mathematics

    Determine the value of -0.4 ÷ 0.3.

    STEP BY STEP SOLUTON
    negative 0.4 space divided by space 0.3
C o n v e r t i n g space d e c i m a l s space i n t o space f r a c t i o n space
space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 3 over 10 space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 10 over 3 space equals space fraction numerator negative 40 over denominator 30 end fraction space equals space 4 over 3

    Determine the value of -0.4 ÷ 0.3.

    MathematicsGrade-7
    STEP BY STEP SOLUTON
    negative 0.4 space divided by space 0.3
C o n v e r t i n g space d e c i m a l s space i n t o space f r a c t i o n space
space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 3 over 10 space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 10 over 3 space equals space fraction numerator negative 40 over denominator 30 end fraction space equals space 4 over 3
    Grade-7
    Mathematics

    The distance between the two numbers represented (in red) on the number line is ______.

    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    |0.2 – 0.7|
    | 0.5|
    0.5 units.

    So, the distance between 0.2 and 0.7 on a number line is 0.5 units 

    The distance between the two numbers represented (in red) on the number line is ______.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    |0.2 – 0.7|
    | 0.5|
    0.5 units.

    So, the distance between 0.2 and 0.7 on a number line is 0.5 units 

    parallel
    Grade-7
    Mathematics

    Edward bought 3 pencils of equal price of $4.20. The price of each pencil is __________.

    STEP  BY STEP SOLUTION
    Price of 3 pencils = $4.20
    Price of 1 pencil = fraction numerator P r i c e space o f space 3 space p e n c i l s space over denominator 3 space p e n c i l s end fraction
    4.20 space divided by space 3
fraction numerator 420 over denominator space 100 end fraction space divided by space 3 over 1 space equals space 420 over 100 space cross times space 1 third space equals space 420 over 300 space equals space 7 over 5

    Edward bought 3 pencils of equal price of $4.20. The price of each pencil is __________.

    MathematicsGrade-7
    STEP  BY STEP SOLUTION
    Price of 3 pencils = $4.20
    Price of 1 pencil = fraction numerator P r i c e space o f space 3 space p e n c i l s space over denominator 3 space p e n c i l s end fraction
    4.20 space divided by space 3
fraction numerator 420 over denominator space 100 end fraction space divided by space 3 over 1 space equals space 420 over 100 space cross times space 1 third space equals space 420 over 300 space equals space 7 over 5
    Grade-7
    Mathematics

    The sum or difference of negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses is _____.

    STEP BY STEP SOLUTION
    negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses
W e space w i l l space c o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space
equals negative 3.5 space plus open parentheses negative 56 over 10 close parentheses
N o w space w e space w i l l space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space w e space c a n space a l s o space t a k e space L C M space a n d space t h e n space s o l v e space
equals negative 3.5 minus 5.6
O n space s i m p l i f y i n g space w e space w i l l space g e t space
equals negative 9.1

    The sum or difference of negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses is _____.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses
W e space w i l l space c o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space
equals negative 3.5 space plus open parentheses negative 56 over 10 close parentheses
N o w space w e space w i l l space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space w e space c a n space a l s o space t a k e space L C M space a n d space t h e n space s o l v e space
equals negative 3.5 minus 5.6
O n space s i m p l i f y i n g space w e space w i l l space g e t space
equals negative 9.1
    Grade-7
    Mathematics

    Determine the value of fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses

    STEP BY STEP SOLUTION
    fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses
O p e n i n g space b r a c k e t s space
space equals space fraction numerator negative 6 over denominator 9 end fraction space minus space 4 over 2 space
T a k i n g space L C M thin space o f space 9 & 2 space left parenthesis i. e space 18 right parenthesis
equals space fraction numerator negative 6 space cross times space 2 space minus space 4 space cross times space 9 over denominator 18 end fraction
space equals space fraction numerator negative 12 space minus space 36 over denominator 18 end fraction space
equals space 48 over 18 space equals space fraction numerator negative 24 over denominator 9 end fraction

    Determine the value of fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses
O p e n i n g space b r a c k e t s space
space equals space fraction numerator negative 6 over denominator 9 end fraction space minus space 4 over 2 space
T a k i n g space L C M thin space o f space 9 & 2 space left parenthesis i. e space 18 right parenthesis
equals space fraction numerator negative 6 space cross times space 2 space minus space 4 space cross times space 9 over denominator 18 end fraction
space equals space fraction numerator negative 12 space minus space 36 over denominator 18 end fraction space
equals space 48 over 18 space equals space fraction numerator negative 24 over denominator 9 end fraction
    parallel
    Grade-7
    Mathematics

    The cost of 7 over 2 meters of cloth is $ 231 over 4. The cost of one meter is __________.

    STEP BY STEP SOLUTION
    Cost of 7 over 2 space m cloth = $231 over 4
    Cost of 1 meter cloth = fraction numerator C o s t space o f space begin display style 7 over 2 end style m space c l o t h space over denominator begin display style 7 over 2 end style m end fraction
    231 over 4 space divided by space 7 over 2 space equals space 231 over 2 space cross times space 2 over 7 space equals space 462 over 14 space equals space 33
    Cost of 1 meter cloth = $33

    The cost of 7 over 2 meters of cloth is $ 231 over 4. The cost of one meter is __________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    Cost of 7 over 2 space m cloth = $231 over 4
    Cost of 1 meter cloth = fraction numerator C o s t space o f space begin display style 7 over 2 end style m space c l o t h space over denominator begin display style 7 over 2 end style m end fraction
    231 over 4 space divided by space 7 over 2 space equals space 231 over 2 space cross times space 2 over 7 space equals space 462 over 14 space equals space 33
    Cost of 1 meter cloth = $33
    Grade-7
    Mathematics

    The sum or difference of negative 2 1 fifth plus 1.03  is ______.

    STEP BY STEP SOLUTION
    negative 2 1 fifth plus 1.03
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space
equals negative 11 over 5 space plus space 1.03
C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l s space
equals negative 2.2 plus 1.03 equals negative 1.17

    The sum or difference of negative 2 1 fifth plus 1.03  is ______.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    negative 2 1 fifth plus 1.03
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space
equals negative 11 over 5 space plus space 1.03
C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l s space
equals negative 2.2 plus 1.03 equals negative 1.17
    Grade-7
    Mathematics

    The cost of each apple is $1 1 half

    STEP BY STEP SOLUTION
    Cost of each apple = $ 1 1 half
    Cost of 8 apples = Cost of 1 apple cross times 8
    1 1 half space cross times space 8 over 1 space equals space 3 over 2 space cross times space 8 over 1 space equals space 24 over 2 space equals space 12
    Cost of 8 apples = $12

    The cost of each apple is $1 1 half

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    Cost of each apple = $ 1 1 half
    Cost of 8 apples = Cost of 1 apple cross times 8
    1 1 half space cross times space 8 over 1 space equals space 3 over 2 space cross times space 8 over 1 space equals space 24 over 2 space equals space 12
    Cost of 8 apples = $12
    parallel

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