Mathematics
Grade-7
Easy

Question

The sum or difference of negative 5.5 minus open parentheses negative 3 1 half close parentheses is _________.

  1. -1.5
  2. 3.5
  3. -4.5
  4. -2.0

Hint:

Follow the BODMASS rule to solve this paticular question.

The correct answer is: -2.0


    STEP BY STEP SOLUTION
    negative 5.5 minus open parentheses negative 3 1 half close parentheses
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals negative 5.5 space minus space open parentheses negative 7 over 2 close parentheses
O p e n i n g space b r a c k e t space
equals space minus 5.5 space plus 7 over 2
C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l space o r space t a k i n g space L C M space
equals negative 5.5 plus 3.5 equals negative 2.0
T h e space a n s w e r space o f space a b o v e space q u e s t i o n space i s space minus 2.0

    Related Questions to study

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    The value of  2 open parentheses negative 4 over 3 close parentheses space divided by space 2 open parentheses negative 6 over 9 close parentheses is _________.

    STEP BY STEP SOLUTION
    2 open parentheses fraction numerator negative 4 over denominator 3 end fraction close parentheses space minus space 2 open parentheses fraction numerator negative 6 over denominator 9 end fraction close parentheses space
M u l t i p l y i n g space 2 space a n d space o p e n i n g space b r a c k e t
equals space minus 8 over 3 space plus 12 over 9 space
T a k i n g space L C M thin space o f space 3 & 9 space left parenthesis i. e space 9 right parenthesis
equals space fraction numerator negative 24 space plus 12 over denominator 9 end fraction space
equals negative space 12 over 9 space equals negative space fraction numerator 4 over denominator space 3 end fraction

    The value of  2 open parentheses negative 4 over 3 close parentheses space divided by space 2 open parentheses negative 6 over 9 close parentheses is _________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    2 open parentheses fraction numerator negative 4 over denominator 3 end fraction close parentheses space minus space 2 open parentheses fraction numerator negative 6 over denominator 9 end fraction close parentheses space
M u l t i p l y i n g space 2 space a n d space o p e n i n g space b r a c k e t
equals space minus 8 over 3 space plus 12 over 9 space
T a k i n g space L C M thin space o f space 3 & 9 space left parenthesis i. e space 9 right parenthesis
equals space fraction numerator negative 24 space plus 12 over denominator 9 end fraction space
equals negative space 12 over 9 space equals negative space fraction numerator 4 over denominator space 3 end fraction
    Grade-7
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    Determine the distance between 2.5 and - 0.5 on the number line shown

    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    So, we will subract -0.5 from 2.5
    |2.5 – (-0.5) | = |2.5 + 0.5| = 3 units.

    Determine the distance between 2.5 and - 0.5 on the number line shown

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    So, we will subract -0.5 from 2.5
    |2.5 – (-0.5) | = |2.5 + 0.5| = 3 units.
    Grade-7
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    The distance between the numbers -4 and 2 on the number line is _____.

    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    open vertical bar negative 4 minus 2 close vertical bar
open vertical bar negative 6 close vertical bar
6

    So, the distance between -4 and 2 is 6 units 

    The distance between the numbers -4 and 2 on the number line is _____.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    open vertical bar negative 4 minus 2 close vertical bar
open vertical bar negative 6 close vertical bar
6

    So, the distance between -4 and 2 is 6 units 

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    Determine the value of -0.4 ÷ 0.3.

    STEP BY STEP SOLUTON
    negative 0.4 space divided by space 0.3
C o n v e r t i n g space d e c i m a l s space i n t o space f r a c t i o n space
space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 3 over 10 space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 10 over 3 space equals space fraction numerator negative 40 over denominator 30 end fraction space equals space 4 over 3

    Determine the value of -0.4 ÷ 0.3.

    MathematicsGrade-7
    STEP BY STEP SOLUTON
    negative 0.4 space divided by space 0.3
C o n v e r t i n g space d e c i m a l s space i n t o space f r a c t i o n space
space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 3 over 10 space equals space fraction numerator negative 4 over denominator 10 end fraction space cross times space 10 over 3 space equals space fraction numerator negative 40 over denominator 30 end fraction space equals space 4 over 3
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    The distance between the two numbers represented (in red) on the number line is ______.

    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    |0.2 – 0.7|
    | 0.5|
    0.5 units.

    So, the distance between 0.2 and 0.7 on a number line is 0.5 units 

    The distance between the two numbers represented (in red) on the number line is ______.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    We know that the distance is the difference between the numbers.
    |0.2 – 0.7|
    | 0.5|
    0.5 units.

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    Edward bought 3 pencils of equal price of $4.20. The price of each pencil is __________.

    STEP  BY STEP SOLUTION
    Price of 3 pencils = $4.20
    Price of 1 pencil = fraction numerator P r i c e space o f space 3 space p e n c i l s space over denominator 3 space p e n c i l s end fraction
    4.20 space divided by space 3
fraction numerator 420 over denominator space 100 end fraction space divided by space 3 over 1 space equals space 420 over 100 space cross times space 1 third space equals space 420 over 300 space equals space 7 over 5

    Edward bought 3 pencils of equal price of $4.20. The price of each pencil is __________.

    MathematicsGrade-7
    STEP  BY STEP SOLUTION
    Price of 3 pencils = $4.20
    Price of 1 pencil = fraction numerator P r i c e space o f space 3 space p e n c i l s space over denominator 3 space p e n c i l s end fraction
    4.20 space divided by space 3
fraction numerator 420 over denominator space 100 end fraction space divided by space 3 over 1 space equals space 420 over 100 space cross times space 1 third space equals space 420 over 300 space equals space 7 over 5
    parallel
    Grade-7
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    The sum or difference of negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses is _____.

    STEP BY STEP SOLUTION
    negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses
W e space w i l l space c o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space
equals negative 3.5 space plus open parentheses negative 56 over 10 close parentheses
N o w space w e space w i l l space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space w e space c a n space a l s o space t a k e space L C M space a n d space t h e n space s o l v e space
equals negative 3.5 minus 5.6
O n space s i m p l i f y i n g space w e space w i l l space g e t space
equals negative 9.1

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    MathematicsGrade-7
    STEP BY STEP SOLUTION
    negative 3.5 plus open parentheses negative 5 6 over 10 close parentheses
W e space w i l l space c o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space
equals negative 3.5 space plus open parentheses negative 56 over 10 close parentheses
N o w space w e space w i l l space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space w e space c a n space a l s o space t a k e space L C M space a n d space t h e n space s o l v e space
equals negative 3.5 minus 5.6
O n space s i m p l i f y i n g space w e space w i l l space g e t space
equals negative 9.1
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    Determine the value of fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses

    STEP BY STEP SOLUTION
    fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses
O p e n i n g space b r a c k e t s space
space equals space fraction numerator negative 6 over denominator 9 end fraction space minus space 4 over 2 space
T a k i n g space L C M thin space o f space 9 & 2 space left parenthesis i. e space 18 right parenthesis
equals space fraction numerator negative 6 space cross times space 2 space minus space 4 space cross times space 9 over denominator 18 end fraction
space equals space fraction numerator negative 12 space minus space 36 over denominator 18 end fraction space
equals space 48 over 18 space equals space fraction numerator negative 24 over denominator 9 end fraction

    Determine the value of fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses

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    fraction numerator negative 6 over denominator 9 end fraction space plus space open parentheses fraction numerator negative 4 over denominator 2 end fraction close parentheses
O p e n i n g space b r a c k e t s space
space equals space fraction numerator negative 6 over denominator 9 end fraction space minus space 4 over 2 space
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space equals space fraction numerator negative 12 space minus space 36 over denominator 18 end fraction space
equals space 48 over 18 space equals space fraction numerator negative 24 over denominator 9 end fraction
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    STEP BY STEP SOLUTION
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    231 over 4 space divided by space 7 over 2 space equals space 231 over 2 space cross times space 2 over 7 space equals space 462 over 14 space equals space 33
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    The sum or difference of negative 2 1 fifth plus 1.03  is ______.

    STEP BY STEP SOLUTION
    negative 2 1 fifth plus 1.03
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space
equals negative 11 over 5 space plus space 1.03
C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l s space
equals negative 2.2 plus 1.03 equals negative 1.17

    The sum or difference of negative 2 1 fifth plus 1.03  is ______.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    negative 2 1 fifth plus 1.03
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space
equals negative 11 over 5 space plus space 1.03
C o n v e r t i n g space f r a c t i o n space i n t o space d e c i m a l s space
equals negative 2.2 plus 1.03 equals negative 1.17
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    The cost of each apple is $1 1 half

    STEP BY STEP SOLUTION
    Cost of each apple = $ 1 1 half
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    1 1 half space cross times space 8 over 1 space equals space 3 over 2 space cross times space 8 over 1 space equals space 24 over 2 space equals space 12
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    MathematicsGrade-7
    STEP BY STEP SOLUTION
    Cost of each apple = $ 1 1 half
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    1 1 half space cross times space 8 over 1 space equals space 3 over 2 space cross times space 8 over 1 space equals space 24 over 2 space equals space 12
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    Grade-7
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    The value of 3 1 half space plus space open parentheses fraction numerator negative 2 over denominator 4 end fraction close parentheses is __________.

    STEP BY STEP SOLUTION
    3 1 half space minus space 2 over 4
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l r space f r a c t i o n space
space equals space 2 over 2 space minus space 2 over 4 space
T a k i n g space L C M space o f space 2 & 4 space left parenthesis i. e space 4 right parenthesis
equals space fraction numerator 14 space minus space 2 over denominator 4 end fraction space equals space 12 over 4 space equals space 3

    The value of 3 1 half space plus space open parentheses fraction numerator negative 2 over denominator 4 end fraction close parentheses is __________.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    3 1 half space minus space 2 over 4
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l r space f r a c t i o n space
space equals space 2 over 2 space minus space 2 over 4 space
T a k i n g space L C M space o f space 2 & 4 space left parenthesis i. e space 4 right parenthesis
equals space fraction numerator 14 space minus space 2 over denominator 4 end fraction space equals space 12 over 4 space equals space 3
    parallel
    Grade-7
    Mathematics

    The sum or difference of  negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses is _______.

    STEP BY STEP SOLUTION
    negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals negative 3.8 minus open parentheses negative 28 over 10 close parentheses
O p e n i n g space b r a c k e t
equals negative 3.8 plus space 28 over 10
N o w space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space t a k e space L C M space
equals negative 3.8 plus 2.8 equals negative 1.0
A n s w e r equals space minus 1.0

    The sum or difference of  negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses is _______.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    negative 3.8 minus open parentheses negative 2 8 over 10 close parentheses
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals negative 3.8 minus open parentheses negative 28 over 10 close parentheses
O p e n i n g space b r a c k e t
equals negative 3.8 plus space 28 over 10
N o w space c o n v e r t space f r a c t i o n space i n t o space d e c i m a l space o r space t a k e space L C M space
equals negative 3.8 plus 2.8 equals negative 1.0
A n s w e r equals space minus 1.0
    Grade-7
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    Determine the value of text  (15)   end text 1 1 fourth space plus space left parenthesis 15 right parenthesis space open parentheses negative 3 over 2 close parentheses .

    STEP BY STEP SOLUTION
    ]text  (15)1  end text 1 fourth plus left parenthesis 15 right parenthesis open parentheses negative 3 over 2 close parentheses
T a k i n g space 15 space c o m m o n space f r o m space b o t h
space equals space 15 open square brackets 1 1 fourth space plus space open parentheses negative 3 over 2 close parentheses close square brackets space
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space a n d space o p e n i n g space b r a c k e t s
equals space 15 open square brackets 5 over 4 space minus space 3 over 2 close square brackets space equals space 15 open square brackets fraction numerator 5 space minus space 6 over denominator 4 end fraction close square brackets space
equals space 15 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses
M i l t i p l y i n g space 15 space i n s i d e space b r a c k e t
space equals space fraction numerator negative 15 over denominator 4 end fraction

    Determine the value of text  (15)   end text 1 1 fourth space plus space left parenthesis 15 right parenthesis space open parentheses negative 3 over 2 close parentheses .

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    ]text  (15)1  end text 1 fourth plus left parenthesis 15 right parenthesis open parentheses negative 3 over 2 close parentheses
T a k i n g space 15 space c o m m o n space f r o m space b o t h
space equals space 15 open square brackets 1 1 fourth space plus space open parentheses negative 3 over 2 close parentheses close square brackets space
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n space a n d space o p e n i n g space b r a c k e t s
equals space 15 open square brackets 5 over 4 space minus space 3 over 2 close square brackets space equals space 15 open square brackets fraction numerator 5 space minus space 6 over denominator 4 end fraction close square brackets space
equals space 15 open parentheses fraction numerator negative 1 over denominator 4 end fraction close parentheses
M i l t i p l y i n g space 15 space i n s i d e space b r a c k e t
space equals space fraction numerator negative 15 over denominator 4 end fraction
    Grade-7
    Mathematics

    The sum or difference of  5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses is _____.

    STEP BY STEP SOLUTION
    5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses
O p e n space t h e space b r a c k e t
equals 5 3 over 4 minus 6 1 fourth
C o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals 23 over 4 space minus space 25 over 4
N o w space t a k i n g space L c m space o r space w e space c a n space c o n v e r t space i t space i n space d e c i m a l s
equals fraction numerator 23 minus 25 over denominator 4 end fraction
equals fraction numerator negative 2 over denominator 4 end fraction space o r space minus 1 half

    The sum or difference of  5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses is _____.

    MathematicsGrade-7
    STEP BY STEP SOLUTION
    5 3 over 4 plus open parentheses negative 6 1 fourth close parentheses
O p e n space t h e space b r a c k e t
equals 5 3 over 4 minus 6 1 fourth
C o n v e r t space m i x e d space f r a c t i o n space i n t o space s i m p l e space f r a c t i o n
equals 23 over 4 space minus space 25 over 4
N o w space t a k i n g space L c m space o r space w e space c a n space c o n v e r t space i t space i n space d e c i m a l s
equals fraction numerator 23 minus 25 over denominator 4 end fraction
equals fraction numerator negative 2 over denominator 4 end fraction space o r space minus 1 half
    parallel

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