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Mathematics

Grade6

Easy

Question

The value of $open parentheses 2 fraction numerator 3 over denominator 4 end fraction divided by 1 fraction numerator 1 over denominator 3 end fraction close parentheses$ is_______.

$\frac{9}{12}$
$\frac{16}{33}$
$\frac{9}{16}$
$\frac{33}{16}$

hint Hint:

When we do division between two fraction, we use reciprocal method.

The correct answer is: $fraction numerator 33 over denominator 16 end fraction$

We have to find the value of the given expression
So,
$open parentheses 2 fraction numerator 3 over denominator 4 end fraction divided by 1 fraction numerator 1 over denominator 3 end fraction close parentheses equals fraction numerator 11 over denominator 4 end fraction divided by fraction numerator 4 over denominator 3 end fraction equals fraction numerator 11 over denominator 4 end fraction cross times fraction numerator 3 over denominator 4 end fraction equals fraction numerator 33 over denominator 16 end fraction$

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