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Mathematics

Grade10

Easy

Question

The value of d if 0.625 (x + 10) - 10 = 0 is ___________.

$- \frac{16.25}{0.625}$
1
$\frac{120}{265}$
5

hint Hint:

0.625x + 6.25 - 10 = 0

The correct answer is: $negative fraction numerator 16.25 over denominator 0.625 end fraction$

0.625 (x + 10) - 10 = 0
0.625x + 6.25 - 10 = 0
0.625x +16.25 = 0
x = $negative fraction numerator 16.25 over denominator 0.625 end fraction$

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