There were x cookies at the beginning of a party. By the end of the party, 16 of them had been eaten. Using x, write an expression for the number of cookies that were left.

Expand the following using distributive property of multiplication: 5(6x − 11)

Given Expression:
5(6x − 11)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to  5(6x − 11):
5(6x − 11)
= 
= (30x) + (-55)
= 30x -55.
Hence, the expression  5(6x − 11) becomes 30x -55 after expansion.

Evaluate the expression for the given value of the variable.
3x + 5 when x = 5

Simplify the following using distributive property of multiplication:
9(3y–4)

Given Expression:
9(3y–4)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which yields ab+ ac as a result.
Similarly, By applying the Distributive Law to 9(3y–4):
9(3y–4)
= 
= (27y) + (-36)
= 27y - 36.
Hence, the expression 9(3y–4) becomes 27y-36 after expansion.

Evaluate 2a + 4b
if a = 10     and    b = 6

Evaluate 3x + 8   if x = 2

Expand the following using distributive property of multiplication:
6(x + 4x)

Given Expression:
6(x + 4x)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which produces ab + ac as a result.
Similarly, By applying the Distributive Law to 6(x + 4x):
6(x + 4x)
= 
= 6x + 24x.
Hence, the expansion of the 6(x + 4x) becomes 6x + 24x.

Evaluate bc + 5a
When a = 3, b = 4, and c = -6

Simplify the following using distributive property of multiplication: 4(3x+5)

Given Expression:
4(3x+5)
Since, The given expression is in the form of a(b+ c) then, we can apply Distributive Law which produces ab+ ac as a result.
Similarly, By applying the Distributive Law to 4(3x+5) :
4(3x+5)
= 
=(12x) + (20)
=12x + 20.
Hence, the expression 4(3x+5) becomes 12x + 20 after it's evaluation.

Expand the following using distributive property of multiplication:
6(12x–7)

Given Expression:
6(12x–7)
Since, it is in the form a(b+ c) we can apply Distributive Law which produce ab+ ac as a result.
Similarly, By applying Distributive Law to 6(12x–7) :
6(12x–7)
= 
= (72x) + (-42)
= 72x - 42.
Hence, the expression 6(12x–7) becomes 72x - 42 after it's expansion.

Expand the following using distributive property of multiplication: 14(8x−3)

Given Expression:
14(8x−3)
Since, the given expression is in the form of a(b+ c) we can apply Distributive Law which produces ab + ac as a result.
* similarly, By applying the Distribution law to 14(8x−3):
14(8x−3)
= 
= (112x) + (-42)
=112x-42.
Hence, the expression 14(8x−3) becomes 112x -42 after it's expansion.

Simplify the following using distributive property of multiplication: 3(9x−5)

Given Expression: 
3(9x−5)
Since, it is in the form of a(b+ c), we can apply Distributive Law which produces ab+ ac as a result.
Similarly, By applying the Distribution Law to 3(9x−5):
3(9x−5)
= 
= (27x)+(-15)
= 27x-15.
Hence, the expression 3(9x−5) becomes 27x-15 after expansion.

Expand 4(8y + 15)

Given Expression:
4(8y + 15)
Since, it is in the form a(b+ c), we can apply Distributive Law of Multiplication which produces ab+ ac as result.
Similarly, By applying the Distribution Law to 4(8y + 15):
4(8y + 15)
= 
= (32y) + (60)
= 32y + 60.
Hence, the expansion of 4(8y + 15) yields 32y + 60.

Simplify the following using distributive property of multiplication: 10 (7m+3n)

Given Expression:
                            10 (7m+3n)
Since, it is in the form of a(b+ c), we can apply distributive law which produces ab +ac as a result.
Similarly, By applying the Distributive Law to a 10 (7m+3n):
10 (7m+3n)
= 
= 70m + 30n.
Hence, the expansion of 10 (7m+3n) is 70m + 30n.

Simplify the following using distributive property of multiplication: 8 (7q+4)

Given Expression:
8 (7q+4)
Since, it is in the form a(b +c) we can apply Distributive Law which produces ab + ac as a result.
Similarly, By applying the Distributive Law to 8 (7q+4) :
8 (7q+4)
= 
= 56q + 32.
Hence, the distribution property of multiplication to 8 (7q+4) yields 56q + 32.

Expand by distributive property. −3(−2a+3)

Given expression:
−3(−2a+3)
Since, it is in the form a(b+ c) we can apply Distribution law which produces ab + ac as result.
Similarly, By applying the Distribution Law to −3(−2a+3) :
−3(−2a+3)
= 
= 
= 6a -9.
Hence, The expression −3(−2a+3) yields 6a -6 after it's expansion.