Question

# What do we get after factorizing x^{2 }+ 6x - 27?

- (x + 9) (x - 3)
- (x - 9) (x + 3)
- (x - 9) (x - 3)
- (x + 9) (x + 3)

## The correct answer is: (x + 9) (x - 3)

STEP BY STEP SOLUTION

To factorize x^{2 }+ 6x - 27, we have to find two numbers, ‘a’ and ‘b,’ such that a + b = 6 and a × b = 27.

For that, we have to find factors of -27, which are ±1, ±3, ±9.

Now we have to arrange two numbers from these numbers such that a + b = 6 and a × b =27.

By considering this, we get two numbers + 9 and - 3

9 + (- 3) = 6 and 9 × - 3 = - 27

Now after manipulating terms, we get x^{2 }+ 9x - 3x - 27.

x^{2 }+ 9x - 3x - 27 = x(x + 9) - 3(x + 9)

= (x + 9)(x - 3).

^{2 }+ 6x - 27, we have to find two numbers, ‘a’ and ‘b,’ such that a + b = 6 and a × b = 27.

Now after manipulating terms, we get x

^{2 }+ 9x - 3x - 27.

x

^{2 }+ 9x - 3x - 27 = x(x + 9) - 3(x + 9)

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