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Mathematics

Grade6

Easy

Question

What is the simplified form of the expression $open parentheses fraction numerator 9 over denominator 7 end fraction divided by fraction numerator 3 over denominator 2 end fraction close parentheses minus open parentheses fraction numerator 15 over denominator 14 end fraction cross times fraction numerator 2 over denominator 5 end fraction close parentheses minus open parentheses fraction numerator 27 over denominator 14 end fraction divided by 4 fraction numerator 1 over denominator 2 end fraction close parentheses$ ?

0
12
7
$\frac{12}{7}$

hint Hint:

We have given an expression, we will solve it using fundamental operation.

The correct answer is: 0

$open parentheses fraction numerator 9 over denominator 7 end fraction divided by fraction numerator 3 over denominator 2 end fraction close parentheses minus open parentheses fraction numerator 15 over denominator 14 end fraction cross times fraction numerator 2 over denominator 5 end fraction close parentheses minus open parentheses fraction numerator 27 over denominator 14 end fraction divided by 4 fraction numerator 1 over denominator 2 end fraction close parentheses equals open parentheses fraction numerator 9 over denominator 7 end fraction cross times fraction numerator 2 over denominator 3 end fraction close parentheses minus open parentheses fraction numerator 3 over denominator 7 end fraction close parentheses minus open parentheses fraction numerator 27 over denominator 14 end fraction cross times fraction numerator 2 over denominator 9 end fraction close parentheses$
$equals fraction numerator 6 over denominator 7 end fraction minus fraction numerator 3 over denominator 7 end fraction minus fraction numerator 3 over denominator 7 end fraction equals fraction numerator 6 minus 3 minus 3 over denominator 7 end fraction equals 0$

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