Mathematics
Grade9
Easy
Question
Which property listed is the reason for the last step in the proof?
GIVEN: ![m angle 1 equals 59 to the power of ring operator end exponent comma m angle 2 equals 59 to the power of ring operator end exponent](data:image/png;base64,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)
PROVE: ![m angle 1 equals m angle 2](data:image/png;base64,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)
Statements | Reasons |
1. |
1. Given |
2. |
2. Symmetric Property of Equality |
3. |
3. _____? |
- Transitive Property of Equality
- Reflexive Property of Equality
- Symmetric Property of Equality
- Distributive Property
Hint:
In this question, we are given m∠1=59° and m∠2=59°. We have to prove that m∠1=m∠2. Here one more thing is given is 59°= m∠1 and this property is symmetric. Match all the property to given condition.
The correct answer is: Transitive Property of Equality
Here we have to find what is property of m∠1=m∠2.
Firstly, we have given that m∠1=59° and m∠2=59°. And 59°= m∠1 and this property is symmetric.
In symmetric , if A = B then B = A as well.
So m∠1=59° and 59°= m∠1 then we can also write m∠2=59° then 59°= m∠2
Here, m∠1=59° and m∠2=59° and also m∠1=m∠2.
Lets here A = m∠1 and B = 59° and C = m∠2
Here , m∠1=59° [A = B]
And, 59°= m∠2 [B = C]
Note, in transition, A =B and B = C then A =C ,
There fore, we can write , m∠1=m∠2 . So the property is Transitive property of Equality.
The correct answer is Transitive property of Equality.
Here we have, find the property of m∠1=m∠2 which is transitive. In transitive if A = B and B = C is given then it is also A = C .