Mathematics

Grade6

Easy

Question

# y + y + y + y + y + y

- 7y
- 8y
- 6y
- 2y

Hint:

### This is an algebraic expression. An algebraic expression consists of two components: a variable and a constant. A variable is a quantity that doesn’t have any fixed value. It takes value according to the conditions. It is denoted by the alphabet. A constant is a quantity with a fixed value. In this question, we are given an expression. We have perform the required operations and find the final value.

## The correct answer is: 6y

### The given expression is y + y + y + y + y + y.

There is one variable in the above expression. The variable is : ‘y’. There are six terms in the above expression. We have to perform the operations between them and find the right answer.

If we see, all the six terms contains a same variable. Such terms with same variables are called as like terms. And the terms with different variables are called as unlike terms.

For like terms, we can perform the operations between their coefficients by keeping y constant. It means we can treat each term as a constant and perform operations like normal operations of the constants.

For the above expression we will keep y constant and add the coefficients of y. There are six ‘y’ with coefficient 1. So we get the following value.

y + y + y + y + y + y = ( 1 + 1 + 1 + 1 + 1 + 1 )

y + y + y + y + y + y = 6y

Therefore, the value of equation is 6y

So option which is ’6y’, is the right option.

We have to be careful about the variables before performing operations. Only like terms can be operated with each other.