Maths-
General
Easy

Question

If the point P open parentheses a squared comma a close parentheses subscript minus,lies in the region corresponding to the acute angle between the lines 2y=x and 4y=x then - .....

  1. a element of left parenthesis 2 comma 4 right parenthesis
  2. a element of left parenthesis 2 comma 6 right parenthesis
  3. a element of left parenthesis 4 comma 6 right parenthesis
  4. a element of left parenthesis 4 comma 8 right parenthesis

hintHint:

When a point lies in between the lines. Then, the point satisfy that the product of values with respect to lines should be less than zero.

The correct answer is: a element of left parenthesis 2 comma 4 right parenthesis


    Given That:
    If the point P open parentheses a squared comma a close parentheses subscript minus,lies in the region corresponding to the acute angle between the lines 2y=x and 4y=x then:
    >>> The joint equation of the two lines x=2y and x=4y becomes:

                  u ≡ x - 2y = 0 and v ≡ x - 4y = 0 is

                  u· v = 0, i.e.,

                 ( x - 2y )·( x - 4y ) = 0. i.e.,

                 x² - 4xy - 2xy + 8y² = 0, i.e.,

                S(x, y) ≡ x² - 6xy + 8y² = 0.... (1)

    If the point P(a², a) lies in the interior of the acute angle formed by these lines, then the value of S(x, y) at P( x=a², y=a ) is negative, i.e.,

     >>> S(a², a) ≡ (a²)² - 6(a²)(a) + 8a² < 0

              ∴ a² ( a² - 6a + 8 ) < 0

              ∴ a² - 6a + 8 < 0

              ∴ ( a - 2 )( a - 4 ) < 0
    >>> Therefore, the range of a is (2,4).

    u ≡ x - 2y = 0 and v ≡ x - 4y = 0
    >>>    S(x, y) ≡ x² - 6xy + 8y² = 0
    >>>     ( a - 2 )( a - 4 ) < 0

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