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Maths-

General

Easy

Question

Rectangle A has an area of 64 square meters. The length and width of rectangle B are 3 times the corresponding length and width of rectangle A. What is the area, in square meters, of rectangle B ?

The correct answer is: 576 sq. meters.

HINT:- Assume length and breadth of rectangle A and get equation in area equation for A and now using the 3 times of length and width condition find length and width of rectangle B and find the area of rectangle B using the previous area equation.
Explanation :- Area of rectangle A is 64 sq. meters
Step 1: assume length and width of rectangle A be l and b respectively
Then area of rectangle = length $cross times$ width = l $cross times$ b = 64 sq. meters (given)
Step 2 : given that the length and widths of rectangle B are 3 times that of rectangle A
So, L= 3l and B= 3b
So the area of rectangle B is= length $cross times$ width of rectangle B = 3l $cross times$ 3b
= 9(l $cross times$ b)
But, l $cross times$ b=64 sq. meters
So, So the area of rectangle B = 9(l $cross times$ b) = 9(64) =576 sq. meters.

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