Maths-
General
Easy

Question


What system of linear equations is represented by the lines shown?

  1. table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell 3 x minus 2 y equals 6 end cell row cell 3 x minus 2 y equals 12 end cell end table
  2. table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell 3 x minus 2 y equals 6 end cell row cell 3 x plus 2 y equals 12 end cell end table
  3. table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell 2 x plus 3 y equals 6 end cell row cell 2 x minus 3 y equals 12 end cell end table
  4. table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell negative 2 x minus 3 y equals 6 end cell row cell negative 2 x plus 3 y equals 12 end cell end table

The correct answer is: table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell 3 x minus 2 y equals 6 end cell row cell 3 x minus 2 y equals 12 end cell end table


    HINT:-The given line passes through 2 sets of points so find the equation of lines from two-points form
    Explanation : The two points is form for finding the equation of a line passing through the two points X1 ,Y1 and  X2 ,Y2 as shown below
    y minus y 1 equals fraction numerator y squared minus y 1 over denominator x 2 minus x 1 end fraction left parenthesis x minus x 1 right parenthesis
    Step 1 : From observing the given graph .The 2 sets of points are {(2,0),(0,-3)} and {(4,0),(0,-6)}
    Step 2 : Finding equation for line passing through {(2,0),(0,-3)}
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell y minus y 1 equals fraction numerator y squared minus y 1 over denominator x 2 minus x 1 end fraction left parenthesis x minus x 1 right parenthesis end cell row cell y minus 0 equals fraction numerator negative 3 minus 0 over denominator 0 minus 2 end fraction left parenthesis x minus 2 right parenthesis end cell end table
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell y equals fraction numerator negative 3 over denominator negative 2 end fraction left parenthesis x minus 2 right parenthesis end cell row cell 2 y equals 3 left parenthesis x minus 2 right parenthesis end cell end table
    therefore 3 x minus 2 y equals 6
    Step 3 : Finding equation for line passing through {(4,0),(0,-6)}
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell y minus y 1 equals fraction numerator y 2 minus y 1 over denominator x 2 minus x 1 end fraction left parenthesis x minus x 1 right parenthesis end cell row cell y minus 0 equals fraction numerator negative 6 minus 0 over denominator 0 minus 4 end fraction left parenthesis x minus 4 right parenthesis end cell row cell y equals fraction numerator negative 6 over denominator negative 4 end fraction left parenthesis x minus 4 right parenthesis end cell row cell y equals 3 over 2 left parenthesis x minus 4 right parenthesis end cell row cell 2 y equals 3 left parenthesis x minus 4 right parenthesis end cell row cell therefore 3 x minus 2 y equals 12 end cell end table
     3 x space minus space 2 y space equals space 6 and 3 x space minus space 2 space y space equals space 12 are the system of linear equations represented in the graph.

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