Question

# In a town there are 2 brothers namely Anand and Suresh. Adding 1/3 rd anand’s age and suresh age would sum up to 10. Also adding Anand’s age together with 1⁄2 of suresh age would sum up to 10. Find Anand and Suresh ages.

Hint:

### let the age of Anand be x years and age of suresh be y years

Adding 1/3 rd anand’s age and suresh age would sum up to 10.

Adding Anand’s age together with 1⁄2 of suresh age would sum up to 10

Find the equations and solve them to find their respective ages.

## The correct answer is: 8 years

### Ans :- age of anand = 6 yrs ; age of suresh = 8 yrs

Explanation :-

let the age of Anand be x years and age of suresh be y years

Step 1:- Frame the equations using the given conditions.

Adding 1/3 rd anand’s age and suresh age would sum up to 10.

So, — Eq1

Adding Anand’s age together with 1⁄2 of suresh age would sum up to 10

So, — Eq2

Step 2:- Eliminate x and find y

Doing, 3(Eq1)-Eq2 to eliminate x.

∴ y = 8

Step 3:- Find x by substituting y= 8 in Eq2

∴ x = 6

∴ age of Anand is 6 years and age of suresh is 8 years .

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