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Question

# (𝑎 + (−3))^{2} =

- 𝑎
^{2} + 6𝑎 + 9 - 𝑎
^{2 }− 6𝑎 + 9 - 𝑎
^{2} − 9 - 𝑎
^{2} + 9

^{2}+ 6𝑎 + 9^{2 }− 6𝑎 + 9^{2}− 9^{2}+ 9Hint:

### The methods used to find the product of binomials are called special products.

Multiplying a number by itself is often called squaring.

For example (*x* + 3)(*x* + 3) = (*x* + 3)2

## The correct answer is: 𝑎^{2 }− 6𝑎 + 9

### (𝑎 + (−3))^{2} can be written as (𝑎 + (−3))(𝑎 + (−3))

(𝑎 + (−3))(𝑎 + (−3)) = a(𝑎 + (−3)) − 3(𝑎 + (−3))

= a(a) + a(-3) - 3(a) - 3(-3)

= a^{2} - 3a - 3a + 3^{2}

= a^{2} - 6a + 9

Final Answer:

The simplified value of (𝑎 + (−3))^{2} is a^{2} - 6a + 9. Hence, option b is correct.

^{2}- 3a - 3a + 3

^{2}

^{2}- 6a + 9

Final Answer:

The simplified value of (𝑎 + (−3))

^{2}is a

^{2}- 6a + 9. Hence, option b is correct.

This question can be easily solved by using the formula

(a - b)2 = a2 - 2ab + b2

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