Maths-
General
Easy

Question

The difference between the sides at right angles in right angled triangle is 14 cm. The area of triangle is 120 cm2 . Calculate the perimeter of triangle

hintHint:

Sides containing right angle are height and base.

The correct answer is: 60 cm


    It is given that difference between perpendicular and base = 14 cm
    i.e. b – h = 14  ⇒  b = 14 + h
    Now, Area of triangle = 120 cm2
    1 half cross times b cross times straight h= 120
    left parenthesis 14 plus h right parenthesis cross times h = 240
    h2 + 14h – 240 = 0
    h = fraction numerator negative b plus-or-minus square root of b squared minus 4 a c end root over denominator 2 a end fraction
    h = fraction numerator negative 14 plus-or-minus square root of 14 squared minus 4 left parenthesis negative 240 right parenthesis end root over denominator 2 end fraction equals fraction numerator negative 14 plus-or-minus square root of 1156 over denominator 2 end fraction equals fraction numerator negative 14 plus-or-minus 34 over denominator 2 end fraction
    h = 10 , - 24
    Since, perpendicular is always positive so h = 10
    Base, B = 14 + 10 = 24
    Using Pythagoras theorem ,
    H2 = B2 + P2
    H2 = 242 + 102 = 576 + 100 = 676
    H = square root of 676 = 26 cm
    Perimeter of triangle = Sum of all sides
    = 24 + 10 + 26 = 60 cm

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