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Maths-

General

Easy

Question

Find the y-intercept of the following function
f(x) = 0.3x² + 0.6x – 0.7

hint Hint:

For a quadratic function is in standard form, f(x)=ax2+bx+c.
The y-intercept is the point where a graph crosses the y-axis. In other words, it is the value of y when x=0.

The correct answer is: -0.7.

We have given a function
f(x) = 0.3x² + 0.6x – 0.7
We will compare the given equation with the standard equation f(x)=ax²+bx+c.
We know that for y intercept , x = 0
So, for finding y- intercept
f(x) = y = 0.3(0)² + 0.6(0) – 0.7
y = -0.7
On comparing with the standard form y-intercept is equal to c
y-intercept of given quadratic function is -0.7.

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