Maths-
General
Easy

Question

Find the y-intercept of the following function
f(x) = 0.3x2 + 0.6x – 0.7

hintHint:

For a quadratic function is in standard form, f(x)=ax2+bx+c.
The y-intercept is the point where a graph crosses the y-axis. In other words, it is the value of y when x=0.
 

The correct answer is: -0.7.


    We have given a function
    f(x) = 0.3x2 + 0.6x – 0.7
    We will compare the given equation with the standard equation f(x)=ax2+bx+c.
    We know that for y intercept , x = 0
    So, for finding y- intercept
    f(x) = y = 0.3(0)2 + 0.6(0) – 0.7
    y = -0.7
    On comparing with the standard form y-intercept is equal to c
    y-intercept of given quadratic function is -0.7.

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