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Question

At the beginning of a study, the number of bacteria in a population is 150,000 . The number of bacteria doubles every hour for a limited period of time. For this period of time, which equation models the number of bacteria y in this population after x hours?

  1. y equals 150 comma 000 to the power of 2 x end exponent
  2. y equals 150 comma 000 left parenthesis 2 right parenthesis to the power of x
  3. y equals x squared plus 150 comma 000
  4. y equals 2 x squared plus 150 comma 000

The correct answer is: y equals 150 comma 000 left parenthesis 2 right parenthesis to the power of x


    Let the bacterial after n hours be An. It is twice the amount of as it was  before 1 hour
    I. e An = 2 (An - 1)
    Given, A0 = 150,000
    A1 = 2 (A0) = 150,000(2)
    A2 = 2 (A1) = 150,000(2)2
    This form as Geometric progression with a = 150,000 and r = 2
    Where n + 1 term in G.P is An= arn = A0(2)n
    Ax = 150,000(2)x we get  y = 150,000(2)x .

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