Maths-
General
Easy

Question

solve for x fraction numerator 3 over denominator x plus 1 end fraction equals fraction numerator 8 over denominator x plus 2 end fraction minus fraction numerator 5 over denominator x plus 3 end fraction

hintHint:

  • Hint:
○ Addition and subtraction of fractions.
○ First make denominator equal.
○ Then perform basic operation to get value of x.

The correct answer is: x = 2


    • Step by step explanation:
    ○ Given:
    Equation: fraction numerator 3 over denominator x plus 1 end fraction equals fraction numerator 8 over denominator x plus 2 end fraction minus fraction numerator 5 over denominator x plus 3 end fraction
    ○ Step 1:
    ○ Make denominator equal on RHS:

    fraction numerator 3 over denominator x plus 1 end fraction equals fraction numerator 8 over denominator x plus 2 end fraction minus fraction numerator 5 over denominator x plus 3 end fraction

    not stretchy rightwards double arrow fraction numerator 3 over denominator x plus 1 end fraction equals fraction numerator 8 left parenthesis x plus 3 right parenthesis over denominator left parenthesis x plus 2 right parenthesis left parenthesis x plus 3 right parenthesis end fraction minus fraction numerator 5 left parenthesis x plus 2 right parenthesis over denominator left parenthesis x plus 3 right parenthesis left parenthesis x plus 2 right parenthesis end fraction

    not stretchy rightwards double arrow fraction numerator 3 over denominator x plus 1 end fraction equals fraction numerator 8 x plus 24 over denominator left parenthesis x plus 2 right parenthesis left parenthesis x plus 3 right parenthesis end fraction minus fraction numerator 5 x plus 10 over denominator left parenthesis x plus 3 right parenthesis left parenthesis x plus 2 right parenthesis end fraction

    not stretchy rightwards double arrow fraction numerator 3 over denominator x plus 1 end fraction equals fraction numerator left parenthesis 8 x plus 24 right parenthesis minus left parenthesis 5 x plus 10 right parenthesis over denominator left parenthesis x plus 2 right parenthesis left parenthesis x plus 3 right parenthesis end fraction

    not stretchy rightwards double arrow fraction numerator 3 over denominator x plus 1 end fraction equals fraction numerator left parenthesis 8 x minus 5 x right parenthesis plus left parenthesis 24 minus 10 right parenthesis over denominator left parenthesis x plus 2 right parenthesis left parenthesis x plus 3 right parenthesis end fraction
    not stretchy rightwards double arrow fraction numerator 3 over denominator x plus 1 end fraction equals fraction numerator 3 x plus 14 over denominator left parenthesis x plus 2 right parenthesis left parenthesis x plus 3 right parenthesis end fraction
    ○ Step 2:
    ○ Cross multiply:

    rightwards double arrow3(x+2)(x+3) = (x+1)(3x+14)

    rightwards double arrow3[x(x+3) + 2(x+3)] = x(3x+14) +1(3x+14)

    rightwards double arrow3[x2 + 3x + 2x + 6] = 3x2+ 14x + 3x + 14

    rightwards double arrow3x2 + 15x + 18 = 3x2 + 17x + 14

    rightwards double arrow3x2 - 3x2 + 18 - 14 = 17x - 15x

    rightwards double arrow4 = 2x

    rightwards double arrowx = 4 over 2

    rightwards double arrowx = 2

    • Final Answer:

    x = 2

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