Maths-
General
Easy

Question

If the equation lambda x squared minus 5 x y plus 6 y squared plus x minus 3 y equals 0 represents a pair of straight lines then their point of intersection is

  1. (-3, -1)
  2. (-1, -3)
  3. (3,1)
  4. (1,3)

hintHint:

First find the value of coefficient of x square and then find the point of intersection.

The correct answer is: (-3, -1)


    Given That:
    If the equation lambda x squared minus 5 x y plus 6 y squared plus x minus 3 y equals 0 represents a pair of straight lines then their point of intersection is
    >>> λx2 – 5xy + 6y2 + x – 3y = 0
    >>> Comparing with general equation, ax2 + 2hxy + by2 + 2gx + 2fy + c = 0
    We get a = λ, h = -5/2, b = 6, g = 1/2, f = -3/2, c = 0
    >>> The condition for straight lines is abc + 2fgh – af2 – bg2 – ch2 = 0
    => λ×6×0 + 2×-3/2×1/2×-5/2 – λ×9/4 – 6×1/4 – 0 = 0
    => 0 + 15/4 – 9λ/4 – 3/2 = 0
    => 9/4 = 9λ/4
    => λ = 1
    >>>> So the equation becomes x2 – 5xy + 6y2 + x – 3y = 0
    => x2 – 3xy – 2xy + 6y2 + x – 3y = 0
    => x(x – 3y) – 2y(x – 3y) + x – 3y =0
    => (x – 3y)(x – 2y + 1) = 0
    So x – 3y = 0 …(i)
    x – 2y + 1 = 0 ..(ii)
    Solving (i) and (ii)
    We get x = -3, y = -1
    >>>The point of intersection of the pair of straight lines x2 – 5xy + 6y2 + x – 3y = 0 is (-3, -1)

    >>>The point of intersection of the pair of straight lines x2 – 5xy + 6y2 + x – 3y = 0 is (-3, -1)

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