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Maths-

General

Easy

Question

A solid is in the form of a right circular cylinder with hemisphere at one end and a cone at the other end. Their common diameter is 3.5 cm and the height of the cylindrical and conical portions are 10 cm and 6 cm respectively .Find the volume of the solid ?

hint Hint:

Volume of cylinder $equals pi r squared h$
Volume of cone $equals 1 third pi r squared h$

The correct answer is: 373.33

Explanation:

We have given A solid is in the form of a right circular cylinder with hemisphere at one end and a cone at the other end. Their common diameter is 3.5cm and the height of the cylindrical and conical portions are 10cm and 6cm respectively.

We have to find the volume of the given solid.

Step 1 of 1:
Height of the cylindrical part and cone are 10cm and 6cm respectively.
Radius of cone, cylinder and hemisphere is 3.5cm
Now, The area of canvas required will be sum of area of hemisphere, cylinder and cone part of the tent.
$A equals 2 pi r squared plus 2 pi r h plus pi r open parentheses square root of h squared plus r squared end root close parentheses$
$equals 2 pi left parenthesis 3.5 right parenthesis squared plus 2 pi left parenthesis 3.5 right parenthesis left parenthesis 10 right parenthesis plus pi left parenthesis 3.5 right parenthesis open parentheses square root of 10 squared plus 6 squared end root close parentheses$
= 373.33cm²

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