Graph f(x) = x² + 2x + 4. What are axis of symmetry, vertex and y-intercept of the function

The correct answer is: 4

                                     
This quadratic function is in standard form, f(x)=ax²+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In f(x)=x²+2x+4, a=1, b=2, and c=4. So, the equation for the axis of symmetry is given by

           X = −(2)/2(1)

    x = - 2/2

x = -1
The equation of the axis of symmetry for f(x)=x²+2x+4 is x = -1.
The x coordinate of the vertex is the same:
h = -1
The y coordinate of the vertex is :

                             k = f(h)

                 k = (h)² + 2(h) + 4

                    k = (-1)² + 2(-1) + 4

           k = 1 – 2 + 4

k = 3
Therefore, the vertex is (-1 , 3)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.
y = (0)² + 2(0) + 4
y = 0 + 0 + 4
y = 4
Therefore, Axis of symmetry is x = -1
Vertex is ( -1 , 3 )
Y- intercept is 4.