Maths-
General
Easy

Question

Twenty seven solid iron spheres , each of radius r and surface area S are melted to form a sphere with surface area S’. Find the i) Radius r’ of the new sphere ii) ratio of S and S’

hintHint:

The surface area of a sphere is 4 pi r squared

The correct answer is: 1:9


    Explanation:
    • We have given twenty seven solid iron spheres , each of radius r and surface area S are melted to form a sphere with surface area S’.
    • We have to find the Radius of new sphere and the ratio of S and S’
    Step 1 of 2:
    We have given 27 solid spheres each of radius r and surface area s
    So,
    (i)
    Volume of each sphere will be
    V equals 27 cross times 4 over 3 pi r cubed
    Volume of big sphere
    V equals 4 over 3 pi r to the power of 13
    So,
    4 over 3 pi r to the power of straight prime 3 end exponent equals 27 cross times 4 over 3 pi r cubed
    r to the power of straight prime equals 3 r
    Step 2 of 2:
    Surface area is 4 pi r squared
    s equals 4 pi r squared and
    equals 4 pi left parenthesis 3 r right parenthesis squared
    equals 36 pi r squared
    Therefore,
    s over s to the power of straight prime equals fraction numerator 4 pi r squared over denominator 36 pi r squared end fraction
    1 over 9
    Or
    1 : 9

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