Maths-
General
Easy

Question

2ax − 15 = 3(x + 5) + 5(x − 1)
In the equation above, a is a constant. If no value of x satisfies the equation, what is the value of a ?

  1. 1
  2. 2
  3. 4
  4. 8

The correct answer is: 4


    ○        The concept used in the question is concept of the equation.
    ○        Given equations are linear equations in two variables.
    ○        In the elimination method, any of the coefficients is first equated and eliminated. After elimination, the equations are solved to obtain the other equation.
    • Step by step explanation:
    ○        Given:
    2ax − 15 = 3(x + 5) + 5(x − 1)
    ○        Step 1:
    ○        Simplify:
    2ax − 15 = 3(x + 5) + 5(x - 1)
    2ax − 15 =  (3x + 15) + (5x - 5)
    2ax − 15 = (3x + 5x) + (15 - 5)
    2ax − 15 = 8x + 10
    2ax − 15 = 8x + 10
    2ax − 8x = 10 + 15
    x(2a -8) = 25
    x = fraction numerator 25 over denominator 2 a minus 8 end fraction
    ○        Step 1:
    ○        For x to not satisfy above equation.
    x should be not defined
    ∴  fraction numerator 25 over denominator 2 a minus 8 end fraction should be not defined
    2a - 8 = 0
    2a = 8
    a = 4
    ∴ a = 4
    • Final Answer:
    Correct option is,
    Option C. 4.

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