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Question

A = open square brackets table row 1 cell tan invisible function application x end cell row cell – tan invisible function application x end cell 1 end table close square brackets then let us define a function f(x) = dt.(ATA–1) then which of the following can not be the value of fraction numerator f open parentheses f open parentheses f open parentheses f............ f left parenthesis x right parenthesis close parentheses close parentheses close parentheses over denominator n t i m e s end fraction is (n ≥ 2)

  1. fn(x)    
  2. 1    
  3. fn–1(x)    
  4. n f(x)    

hintHint:

Here, using the Formula open vertical bar A close vertical bar equals open vertical bar A to the power of T close vertical bar space a n d space open vertical bar A to the power of negative 1 end exponent close vertical bar space equals fraction numerator 1 over denominator open vertical bar A close vertical bar end fraction find the value of F(x) in terms of determinant of A and substitute the value of |A| to find the value of function.

The correct answer is: n f(x)


    Given,  f(x) = dt.(AT A-1)  then f(x) = |AT| * |A-1|
    using the Formula open vertical bar A close vertical bar equals open vertical bar A to the power of T close vertical bar space a n d space open vertical bar A to the power of negative 1 end exponent close vertical bar space equals fraction numerator 1 over denominator open vertical bar A close vertical bar end fraction
    Then f(x)space equals open vertical bar A close vertical bar asterisk times fraction numerator 1 over denominator open vertical bar A close vertical bar end fraction space equals space 1
    Here, value of fraction numerator f open parentheses f open parentheses f open parentheses f............ f left parenthesis x right parenthesis close parentheses close parentheses close parentheses over denominator n t i m e s end fraction is 1
    But, By option checking n f(x) = n , where n ≥ 2
    So, value of fraction numerator f open parentheses f open parentheses f open parentheses f............ f left parenthesis x right parenthesis close parentheses close parentheses close parentheses over denominator n t i m e s end fraction cannot be n f(x).

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