Maths-
General
Easy
Question
A ball is tossed into the air. The function f(x)= -16x2 +4x+5 represents the height in feet of the ball x seconds after it is thrown. At what height was the ball tossed into the air ?
The correct answer is: C= 5
Solution:-
We have given a function of a ball which is tossed in air which represents the height in feet of ball x seconds after it is thrown .
So, when the ball was tossed x = 0
So for x= 0 the value of function will be y- intercept
The standard quadratic form is ax2+bx+c=y
In this the term c gives us the y-intercept of the curve
The given function is
f(x)= -16x2 +4x+5
In the given case c gives the height from which the ball is thrown.
C= 5
So, height from which the ball is tossed is 5 feets.
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