Question

# ABC is an equilateral triangle such that the vertices B and C lie on two parallel lines at a distance 6 If A lies between the parallel lines at a distance 4 from one of them then the length of a side of the equilateral triangle is

- 8
- None of these

Hint:

### In equilateral triangle the sides and the angles remains equal and then apply these and then evaluate the side of a triangle.

## The correct answer is:

### Given That:

$BO=6$ and $OA=4$

>>> Let length of side of $ΔABC=a$

$acosθ=6$ ----(1)

$∠ABO=90−(60+θ)$

$=30−θ$

>>>So, $a(sin(30−θ))=4$ ----(2)

>>> from 1 and 2, we get:

a() = 4

>>>

a =

>>> Therefore, the value of a is .

$>>> acosθ=6$ ----(1)

$>>> a(sin(30−θ))=4$ ----(2)

>>> a =

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