Maths-
General
Easy

Question

Class A was given a sunflower with a height of 10 centimeters that grows at a rate of 3.5 cm per week. Class B was given a sunflower with height of 15 centimeters that grows at a rate of 3.25 cm per week After how many weeks are the sunflowers the same height?

Hint:

○ Form the equation according to given information..
○ Take variable values as x or any alphabet.
○ Solve the equation to get value of x.

The correct answer is: ⇒ x = 20


    ○ Given:
    Class A:
    Initial height of sunflower = 10 cm
    Rate of growth = 3.5 cm per week
    Class B:
    Initial height of sunflower = 15 cm
    Rate of growth = 3.25 cm per week
    ○    Step 1:
    ○    Let us consider after x weeks height will be same.
    First consider case of sunflower of class A
    Height after x weeks will be
    rightwards double arrow(10 + 3.5x )
    Now consider case of sunflower of class B
    Height after x weeks will be
    rightwards double arrow(15 + 3.25x )
    ○ Step 2:
    ○ Equate height of sunflowers.
    rightwards double arrow(10 + 3.5x ) = ( 15 + 3.25x )
    rightwards double arrow(3.5x - 3.25x ) = ( 15 - 10 )
    rightwards double arrow0.25x  = 5
    rightwards double arrow(0.25x ) = ( 15 - 10 )
    rightwards double arrowx = fraction numerator 5 over denominator 0.25 end fraction
    rightwards double arrowx = 20
    • Final Answer:
    Hence, after x weeks height of both sunflower will be same.

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