Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

Compute the value of x in the given figure.

$110^{\circ}$
$130^{\circ}$
$120^{\circ}$
$115^{\circ}$ .

hint Hint:

Using the property, “an exterior angle of a triangle is equal to the sum of its two opposite interior angles”.

The correct answer is: $130 to the power of ring operator end exponent$

Detailed Solution
In the given figure, $angle D C B space equals 45 degree comma space space space space space space space space space angle C B A space equals 45 degree comma space space space space space space space space space angle B A D space equals 35 degree$
Here we will produce AD to meet BC at E

Now using angle sum property of the triangle
In $triangle A E B$ ,
$angle B A E space plus space angle A E B plus space angle E B A space equals 180 degree angle A E B space plus 35 degree plus 45 degree equals 180 degree angle A E B plus 80 degree equals 180 degree angle A E B equals 180 degree minus 80 degree angle A E B equals 100 degree$
Further, BEC is a straight line. So, using the property, “the angles forming a linear pair are supplementary”, we get

$angle A E B plus angle A E C equals 180 degree 100 degree plus angle A E C equals 180 degree angle A E C equals 180 degree minus 100 degree angle A E C equals 80 degree$

Also, using the property, “an exterior angle of a triangle is equal to the sum of its two opposite interior angles”. In ΔDEC, x is its exterior angle. Thus,
$angle x equals angle D C E plus angle D E C space space space space space space equals 50 degree plus 80 degree space space space space space space equals 130 degree$

Related Questions to study

Compute the value of x in the given figure.

The value of x=88^o

Compute the value of x in the given figure.

The value of x=88^o

Compute the value of x in the given figure.

Hence option B is correct

Compute the value of x in the given figure.

Hence option B is correct

Compute the value of x in the given figure.

Choice 4 is correct

Compute the value of x in the given figure.

Choice 4 is correct

parallel

In the given figure, if $P Q parallel to R S comma angle M X Q equals 135 to the power of ring operator end exponent$ and $angle M Y R equals 40 to the power of ring operator end exponent$ then the value of $angle X M Y$ is

Hence 85^o is correct option

In the given figure, if $P Q parallel to R S comma angle M X Q equals 135 to the power of ring operator end exponent$ and $angle M Y R equals 40 to the power of ring operator end exponent$ then the value of $angle X M Y$ is

Hence 85^o is correct option

In figure, if $A B parallel to C D comma C D parallel to E F$ and y : z = 3 : 7, x = ?

Hence x=126 choice 4 is correct

In figure, if $A B parallel to C D comma C D parallel to E F$ and y : z = 3 : 7, x = ?

Hence x=126 choice 4 is correct

In figure, if $A B parallel to D E comma angle B A C equals 35 to the power of ring operator end exponent$ and $angle C D E equals 53 to the power of ring operator end exponent comma angle D C E$ = ?

Hence 92^o
is correct choice

In figure, if $A B parallel to D E comma angle B A C equals 35 to the power of ring operator end exponent$ and $angle C D E equals 53 to the power of ring operator end exponent comma angle D C E$ = ?

Hence 92^o
is correct choice

parallel

In figure, sides QP and RQ of $triangle P Q R$ are produced to points S and T respectively. If $angle S P R equals 135 to the power of ring operator end exponent$ and $angle P Q T equals 110 to the power of ring operator end exponent comma angle P R Q$ =?

Hence choice A is correct

In figure, sides QP and RQ of $triangle P Q R$ are produced to points S and T respectively. If $angle S P R equals 135 to the power of ring operator end exponent$ and $angle P Q T equals 110 to the power of ring operator end exponent comma angle P R Q$ =?

Hence choice A is correct

A conductor PQ carries a current 'i' is placed perpendicular to a long conductor XY carrying a current I. The direction of force on PQ will be :–

A conductor PQ carries a current 'i' is placed perpendicular to a long conductor XY carrying a current I. The direction of force on PQ will be :–

physics-General

A circular current loop of radius a is placed in a radial field B as shown. The net force acting on the loop is

A circular current loop of radius a is placed in a radial field B as shown. The net force acting on the loop is

physics-General

parallel

All straight wires are very long. Both AB and CD are arcs of the same circle, both subtending right angles at the centre O. Then the magnetic field at O is–

All straight wires are very long. Both AB and CD are arcs of the same circle, both subtending right angles at the centre O. Then the magnetic field at O is–

physics-General

A steady current is set up in a cubic network composed of wires of equal resistance and length d as shown in figure. What is the magnetic field at the centre P due to the cubic network ?

A steady current is set up in a cubic network composed of wires of equal resistance and length d as shown in figure. What is the magnetic field at the centre P due to the cubic network ?

physics-General

An infinitely long straight conductor is bent into the shape as shown in figure. It carries a current I ampere and the radius of the circular loop is r meter. Then the magnetic induction at the centre of the circular part is

An infinitely long straight conductor is bent into the shape as shown in figure. It carries a current I ampere and the radius of the circular loop is r meter. Then the magnetic induction at the centre of the circular part is

physics-General

parallel

chemistry-General

What is A in the following reaction?

What is A in the following reaction?

chemistry-General

chemistry-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.