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Maths-

General

Easy

Question

Dimensions of a room are 5m $cross times$ 12m $cross times$ 7m, calculate the diagonal of the room and cost of flooring at the room Rs 2

$\sqrt{218, 168}$
$\sqrt{168}, 218$
$\sqrt{418}, 268$
$\sqrt{268, 218}$

hint Hint:

Diagonal of cube=√3×side=√3a unit

The correct answer is: $square root of 218 comma 168 end root$

The dimensions of the room are
Length = 5m
Breadth = 12m
Height = 7m
We know that
Length of the longest pole = length of diagonal = √ (l² + b² + h²)
By substituting the values
Length of the longest pole = √ (5² + 12² + 7²)
So we get
Length of the longest pole = √ (25 + 144 + 49)
By addition
Length of the longest pole = √ 218 m
Base area = lb=12×7=84 m²
Therefore, cost of flooring = 84×2=Rs.168.
Therefore the correct option is a) √218, 168

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