Maths-

General

Easy

Question

# Divide the sum of and by the product and

Hint:

### Perform the operations given in the question and get the final solution.

## The correct answer is: 2/5

### To perform:

Sum of and

…(i)

Product of and

…(ii)

On dividing, (i) by (ii) we have

=

Hence

Product of and

On dividing, (i) by (ii) we have

Hence

### Related Questions to study

Maths-

### Express 0.3178 in the form of p/q. Where p and q are integers.

As 0.3178 is a terminating decimal so it can be expressed as p/q form.

Step 1 of 2:

Write down 0.3178 divided by 1:

Step 2 of 2:

Multiplying numerator and denominator by 104(because there are 4 digits after the decimal point)

Simplifying the fraction:

Final Answer:

Hence, the p/q form of 0.3178 is

Step 1 of 2:

Write down 0.3178 divided by 1:

Step 2 of 2:

Multiplying numerator and denominator by 104(because there are 4 digits after the decimal point)

Simplifying the fraction:

Final Answer:

Hence, the p/q form of 0.3178 is

### Express 0.3178 in the form of p/q. Where p and q are integers.

Maths-General

As 0.3178 is a terminating decimal so it can be expressed as p/q form.

Step 1 of 2:

Write down 0.3178 divided by 1:

Step 2 of 2:

Multiplying numerator and denominator by 104(because there are 4 digits after the decimal point)

Simplifying the fraction:

Final Answer:

Hence, the p/q form of 0.3178 is

Step 1 of 2:

Write down 0.3178 divided by 1:

Step 2 of 2:

Multiplying numerator and denominator by 104(because there are 4 digits after the decimal point)

Simplifying the fraction:

Final Answer:

Hence, the p/q form of 0.3178 is

Maths-

### One liter of petrol costs Rs. 70. What is the cost of 70 litres of petrol

Cost of 1 litre petrol = 70 Rs

cost of 70 litres of petrol = 70 70 = 4900 Rs

cost of 70 litres of petrol = 70 70 = 4900 Rs

### One liter of petrol costs Rs. 70. What is the cost of 70 litres of petrol

Maths-General

Cost of 1 litre petrol = 70 Rs

cost of 70 litres of petrol = 70 70 = 4900 Rs

cost of 70 litres of petrol = 70 70 = 4900 Rs

Maths-

### Insert 3 rational numbers between 3 and 4

Given numbers are 3 and 4.

So

Then,

Hence , required 3 rational numbers between 3 and 4 =

So

Then,

Hence , required 3 rational numbers between 3 and 4 =

### Insert 3 rational numbers between 3 and 4

Maths-General

Given numbers are 3 and 4.

So

Then,

Hence , required 3 rational numbers between 3 and 4 =

So

Then,

Hence , required 3 rational numbers between 3 and 4 =

Maths-

### Uma earns Rs. 16000 per month. She spends of her income on food, of the remainder on house rent and of the remainder on the education of children. How much money is left with her?

Total money earned by Uma = 16000 Rs

Money spent on food from her income = Rs

Amount left with her = Rs

Money spent on house rent from the remaining money = Rs

Amount left with her = 12000 - 3600 = 8400 Rs

Money spent on education of children from the remaining money = Rs

Amount left with her = 8400 - 2000 = 6400 Rs

Money still left with her = 6400 Rs

Money spent on food from her income = Rs

Amount left with her = Rs

Money spent on house rent from the remaining money = Rs

Amount left with her = 12000 - 3600 = 8400 Rs

Money spent on education of children from the remaining money = Rs

Amount left with her = 8400 - 2000 = 6400 Rs

Money still left with her = 6400 Rs

### Uma earns Rs. 16000 per month. She spends of her income on food, of the remainder on house rent and of the remainder on the education of children. How much money is left with her?

Maths-General

Total money earned by Uma = 16000 Rs

Money spent on food from her income = Rs

Amount left with her = Rs

Money spent on house rent from the remaining money = Rs

Amount left with her = 12000 - 3600 = 8400 Rs

Money spent on education of children from the remaining money = Rs

Amount left with her = 8400 - 2000 = 6400 Rs

Money still left with her = 6400 Rs

Money spent on food from her income = Rs

Amount left with her = Rs

Money spent on house rent from the remaining money = Rs

Amount left with her = 12000 - 3600 = 8400 Rs

Money spent on education of children from the remaining money = Rs

Amount left with her = 8400 - 2000 = 6400 Rs

Money still left with her = 6400 Rs

Maths-

### Convert into decimal and identify whether it is a non-terminating and repeating decimal or a terminating decimal:

Let’s say x =

The given rational number is not in its simplified form. So, let’s first covert it in the simplified form

Upon dividing 1 by 4 we got

The resultant decimal is a terminating decimal

Final Answer:

As the resultant decimal has a finite number of digits following the decimal. Hence, the decimal value of is 0.25 and it is a terminating decimal.

The given rational number is not in its simplified form. So, let’s first covert it in the simplified form

Upon dividing 1 by 4 we got

The resultant decimal is a terminating decimal

Final Answer:

As the resultant decimal has a finite number of digits following the decimal. Hence, the decimal value of is 0.25 and it is a terminating decimal.

### Convert into decimal and identify whether it is a non-terminating and repeating decimal or a terminating decimal:

Maths-General

Let’s say x =

The given rational number is not in its simplified form. So, let’s first covert it in the simplified form

Upon dividing 1 by 4 we got

The resultant decimal is a terminating decimal

Final Answer:

As the resultant decimal has a finite number of digits following the decimal. Hence, the decimal value of is 0.25 and it is a terminating decimal.

The given rational number is not in its simplified form. So, let’s first covert it in the simplified form

Upon dividing 1 by 4 we got

The resultant decimal is a terminating decimal

Final Answer:

As the resultant decimal has a finite number of digits following the decimal. Hence, the decimal value of is 0.25 and it is a terminating decimal.

Maths-

### In a school, 𝑡ℎ of the students are boys, if there are 240 girls, find the number of boys in the school?

Let the total number of students = x

Number of girls = 240

So, number of boys = x - 240…(i)

Given that of the total students are boys. That is, …(ii)

On equating (i) and (ii) , we get

Multiply by 8 on both sides.

We have

Hence total number of students = 640

From (ii), we get total number of boys

So, number of boys in the school = 400

Number of girls = 240

So, number of boys = x - 240…(i)

Given that of the total students are boys. That is, …(ii)

On equating (i) and (ii) , we get

Multiply by 8 on both sides.

We have

Hence total number of students = 640

From (ii), we get total number of boys

So, number of boys in the school = 400

### In a school, 𝑡ℎ of the students are boys, if there are 240 girls, find the number of boys in the school?

Maths-General

Let the total number of students = x

Number of girls = 240

So, number of boys = x - 240…(i)

Given that of the total students are boys. That is, …(ii)

On equating (i) and (ii) , we get

Multiply by 8 on both sides.

We have

Hence total number of students = 640

From (ii), we get total number of boys

So, number of boys in the school = 400

Number of girls = 240

So, number of boys = x - 240…(i)

Given that of the total students are boys. That is, …(ii)

On equating (i) and (ii) , we get

Multiply by 8 on both sides.

We have

Hence total number of students = 640

From (ii), we get total number of boys

So, number of boys in the school = 400

Maths-

### If 24 pairs of trousers of equal size can be prepared with 54 m of cloth, what length of cloth is required for each pair of trousers?

Let the cloth required for one trouser = x meters

Then the cloth required for 24 equal size trousers = 54 m

That is, 24x = 54

On dividing both the sides by 24, we get

Hence, cloth required for one trouser

Then the cloth required for 24 equal size trousers = 54 m

That is, 24x = 54

On dividing both the sides by 24, we get

Hence, cloth required for one trouser

### If 24 pairs of trousers of equal size can be prepared with 54 m of cloth, what length of cloth is required for each pair of trousers?

Maths-General

Let the cloth required for one trouser = x meters

Then the cloth required for 24 equal size trousers = 54 m

That is, 24x = 54

On dividing both the sides by 24, we get

Hence, cloth required for one trouser

Then the cloth required for 24 equal size trousers = 54 m

That is, 24x = 54

On dividing both the sides by 24, we get

Hence, cloth required for one trouser

Maths-

### Convert into decimal and identify whether it is a non-terminating and repeating decimal or a terminating decimal:

Let’s say x =

Upon dividing 24 by 11 we got

The resultant decimal is a non-terminating and repeating decimal.

Final Answer:

As the resultant decimal has an infinite number of digits following the decimal and these digits are repeated after a fixed interval. Hence, the decimal value of is and it is a non-terminating and repeating decimal.

Upon dividing 24 by 11 we got

The resultant decimal is a non-terminating and repeating decimal.

Final Answer:

As the resultant decimal has an infinite number of digits following the decimal and these digits are repeated after a fixed interval. Hence, the decimal value of is and it is a non-terminating and repeating decimal.

Maths-General

Let’s say x =

Upon dividing 24 by 11 we got

The resultant decimal is a non-terminating and repeating decimal.

Final Answer:

As the resultant decimal has an infinite number of digits following the decimal and these digits are repeated after a fixed interval. Hence, the decimal value of is and it is a non-terminating and repeating decimal.

Upon dividing 24 by 11 we got

The resultant decimal is a non-terminating and repeating decimal.

Final Answer:

As the resultant decimal has an infinite number of digits following the decimal and these digits are repeated after a fixed interval. Hence, the decimal value of is and it is a non-terminating and repeating decimal.

Maths-

### By what rational number should be multiplied to obtain ?

**Complete step by step solution:**

Given rational number = and let the other rational number be x

On multiplication, we get the result to be

That is, we have

On dividing both sides by ,

Given rational number = and let the other rational number be x

On multiplication, we get the result to be

That is, we have

On dividing both sides by ,

we get

So, must be multiplied with to get .

**By what rational number should be multiplied to obtain ?**

**Maths-General**

**Complete step by step solution:**

Given rational number = and let the other rational number be x

On multiplication, we get the result to be

That is, we have

On dividing both sides by ,

Given rational number = and let the other rational number be x

On multiplication, we get the result to be

That is, we have

On dividing both sides by ,

we get

So, must be multiplied with to get .

Maths-

### By what rational number should be multiplied to obtain ?

**Complete step by step solution:**

Given rational number = and let the other rational number be x

On multiplication, we get the result to be

That is, we have

On dividing both sides by ,

Given rational number = and let the other rational number be x

On multiplication, we get the result to be

That is, we have

On dividing both sides by ,

we get

So, must be multiplied with to get .

**By what rational number should be multiplied to obtain ?**

**Maths-General**

**Complete step by step solution:**

Given rational number = and let the other rational number be x

On multiplication, we get the result to be

That is, we have

On dividing both sides by ,

Given rational number = and let the other rational number be x

On multiplication, we get the result to be

That is, we have

On dividing both sides by ,

we get

So, must be multiplied with to get .

### Convert into decimal and identify whether it is a non-terminating and repeating decimal or a terminating decimal:

### Convert into decimal and identify whether it is a non-terminating and repeating decimal or a terminating decimal:

### Find the cost of 3 m of cloth at Rs 36. per meter.

### Find the cost of 3 m of cloth at Rs 36. per meter.

### The circumference of a circle is 123.2 cm. Calculate (i) the radius of the circle in cm. (ii) the area of the circle, correct to nearest cm

### The circumference of a circle is 123.2 cm. Calculate (i) the radius of the circle in cm. (ii) the area of the circle, correct to nearest cm

Maths-

Let’s say x =

Upon dividing 59 by 8 we got

The resultant decimal is a terminating decimal

Final Answer:

As the resultant decimal has a finite number of digits following the decimal. Hence, the decimal value of is 7.375 and it is a terminating decimal.

Upon dividing 59 by 8 we got

The resultant decimal is a terminating decimal

Final Answer:

As the resultant decimal has a finite number of digits following the decimal. Hence, the decimal value of is 7.375 and it is a terminating decimal.

Maths-General

Let’s say x =

Upon dividing 59 by 8 we got

The resultant decimal is a terminating decimal

Final Answer:

As the resultant decimal has a finite number of digits following the decimal. Hence, the decimal value of is 7.375 and it is a terminating decimal.

Upon dividing 59 by 8 we got

The resultant decimal is a terminating decimal

Final Answer:

As the resultant decimal has a finite number of digits following the decimal. Hence, the decimal value of is 7.375 and it is a terminating decimal.

Maths-

### A sim earns Rs. 40000 per month. He spends of his income on food, of the remaining on education of children and of the remainder on the house rent. How much money is still left with him?

Total money earned by Asim = 40000 Rs

Money spent on food from his income = Rs

Amount left with him = 40000 - 16000 = 24000 Rs

Money spent on education of children from the remaining money = Rs

Amount left with him = 24000 - 10000 = 14000 Rs

Money spent on house rent from the remaining money =

Amount left with him = 14000 - 6000 = 8000 Rs

Money still left with him = 8000 Rs

Money spent on food from his income = Rs

Amount left with him = 40000 - 16000 = 24000 Rs

Money spent on education of children from the remaining money = Rs

Amount left with him = 24000 - 10000 = 14000 Rs

Money spent on house rent from the remaining money =

Amount left with him = 14000 - 6000 = 8000 Rs

Money still left with him = 8000 Rs

### A sim earns Rs. 40000 per month. He spends of his income on food, of the remaining on education of children and of the remainder on the house rent. How much money is still left with him?

Maths-General

Total money earned by Asim = 40000 Rs

Money spent on food from his income = Rs

Amount left with him = 40000 - 16000 = 24000 Rs

Money spent on education of children from the remaining money = Rs

Amount left with him = 24000 - 10000 = 14000 Rs

Money spent on house rent from the remaining money =

Amount left with him = 14000 - 6000 = 8000 Rs

Money still left with him = 8000 Rs

Money spent on food from his income = Rs

Amount left with him = 40000 - 16000 = 24000 Rs

Money spent on education of children from the remaining money = Rs

Amount left with him = 24000 - 10000 = 14000 Rs

Money spent on house rent from the remaining money =

Amount left with him = 14000 - 6000 = 8000 Rs

Money still left with him = 8000 Rs

Maths-

### Find the cost of 3 m of cloth at Rs 36. per meter.

Given that the cost of 1 m of cloth

∴ Cost of

= 124.93 Rs

Hence cost of meter = Rs

∴ Cost of

= 124.93 Rs

Hence cost of meter = Rs

### Find the cost of 3 m of cloth at Rs 36. per meter.

Maths-General

Given that the cost of 1 m of cloth

∴ Cost of

= 124.93 Rs

Hence cost of meter = Rs

∴ Cost of

= 124.93 Rs

Hence cost of meter = Rs

Maths-

### Find the area of circular ring whose external and internal radii are 10cm and 3 cm respectively

It is given that External radii, r

Internal radii, r

Area of circular ring = Area of outer ring – Area of inner ring

= (r

= × (r

= × (10

= × 91 = 286 cm

_{1}= 10 cmInternal radii, r

_{2}= 3 cmArea of circular ring = Area of outer ring – Area of inner ring

= (r

_{1})^{2}- r^{2 }= × (r

_{1})^{2}- × (r_{2})^{2}= × (10

^{2}– 3^{2})= × 91 = 286 cm

^{2}### Find the area of circular ring whose external and internal radii are 10cm and 3 cm respectively

Maths-General

It is given that External radii, r

Internal radii, r

Area of circular ring = Area of outer ring – Area of inner ring

= (r

= × (r

= × (10

= × 91 = 286 cm

_{1}= 10 cmInternal radii, r

_{2}= 3 cmArea of circular ring = Area of outer ring – Area of inner ring

= (r

_{1})^{2}- r^{2 }= × (r

_{1})^{2}- × (r_{2})^{2}= × (10

^{2}– 3^{2})= × 91 = 286 cm

^{2}Maths-

### The circumference of a circle is 123.2 cm. Calculate (i) the radius of the circle in cm. (ii) the area of the circle, correct to nearest cm^{2}

It is given that Circumference of the circle = 123.2 cm

(i). Circumference of the circle = 2 r

123.2 = 2 × × r

19.6 = r

(ii) Area of circle = r

= × (19.6)

= 1207.36 cm

(i). Circumference of the circle = 2 r

123.2 = 2 × × r

19.6 = r

(ii) Area of circle = r

^{2}= × (19.6)

^{2}= 1207.36 cm

^{2}### The circumference of a circle is 123.2 cm. Calculate (i) the radius of the circle in cm. (ii) the area of the circle, correct to nearest cm^{2}

Maths-General

It is given that Circumference of the circle = 123.2 cm

(i). Circumference of the circle = 2 r

123.2 = 2 × × r

19.6 = r

(ii) Area of circle = r

= × (19.6)

= 1207.36 cm

(i). Circumference of the circle = 2 r

123.2 = 2 × × r

19.6 = r

(ii) Area of circle = r

^{2}= × (19.6)

^{2}= 1207.36 cm

^{2}

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