Maths-
General
Easy

Question

Divide the sum of 13 over 5 and fraction numerator negative 12 over denominator 7 end fraction by the product fraction numerator negative 31 over denominator 7 end fraction and fraction numerator 1 over denominator negative 2 end fraction

hintHint:

Perform the operations given in the question and get the final solution.

The correct answer is: 2/5


    To perform: fraction numerator 13 over 5 plus fraction numerator negative 12 over denominator 7 end fraction over denominator fraction numerator negative 31 over denominator 7 end fraction cross times fraction numerator 1 over denominator negative 2 end fraction end fraction
    Sum of 13 over 5 and fraction numerator negative 12 over denominator 7 end fraction equals 13 over 5 plus fraction numerator negative 12 over denominator 7 end fraction

    not stretchy rightwards double arrow fraction numerator 13 cross times 7 plus 5 cross times negative 12 over denominator 5 cross times 7 end fraction

    not stretchy rightwards double arrow fraction numerator 91 plus negative 60 over denominator 35 end fraction

    not stretchy rightwards double arrow 31 over 35…(i)
    Product of fraction numerator negative 31 over denominator 7 end fraction and fraction numerator 1 over denominator negative 2 end fraction equals fraction numerator negative 1 over denominator 2 end fraction equals fraction numerator negative 31 over denominator 7 end fraction cross times fraction numerator negative 1 over denominator 2 end fraction

    not stretchy rightwards double arrow fraction numerator 31 cross times 1 over denominator 7 cross times 2 end fraction

    not stretchy rightwards double arrow 31 over 14…(ii)
    On dividing, (i) by (ii)  we have

    thereforefraction numerator 13 over 5 plus fraction numerator negative 12 over denominator 7 end fraction over denominator fraction numerator negative 31 over denominator 7 end fraction cross times fraction numerator 1 over denominator negative 2 end fraction end fraction = 31 over 35 divided by 31 over 14

    not stretchy rightwards double arrow 31 over 35 cross times 14 over 31

    not stretchy rightwards double arrow 14 over 35 equals 2 over 5
    Hence fraction numerator 13 over 5 plus fraction numerator negative 12 over denominator 7 end fraction over denominator fraction numerator negative 31 over denominator 7 end fraction cross times fraction numerator 1 over denominator negative 2 end fraction end fraction equals 2 over 5

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