Question

# Find the amount to be paid at the end of 3 years, if principal is Rs 1800 at 9% p.a.

Hint:

### Use the formula for simple interest and then find the total amount.

## The correct answer is: 2286 Rupees

### Complete step by step solution:

We calculate simple interest by the formula,…(i)

where P is Principal amount, T is number of years and R is rate of interest

Here, we have T = 3,R = 9% and P = 1800

On substituting the known values in (i), we get

We have SI = 486 Rupees.

We know the formula for total amount = A = P +SI…(ii)

where A is the total amount, P is the principal amount and SI is simple interest.

On substituting the known values in (ii), we get A = 1800 + 486 = 2286

Hence total amount to be paid after 3 years = A = 2286 Rupees.

### Related Questions to study

### Find the compound interest for 3 years on Rs 5000, if the rate of interest for the successive years are 8%, 6% and 10% respectively.

Given that principal amount P = 5000

Number of years T = 3

Let R

_{1}= 8%,R

_{2}= 6% and R

_{3}= 10%

Total amount , …(i)

On substituting the known values in (i), we get

We know that, Compound interest ( CI) = total amount (A) - principal amount (P)

So, Compound interest ( CI) = 6296.4 - 5000 = 1296.4 Rupees

### Find the compound interest for 3 years on Rs 5000, if the rate of interest for the successive years are 8%, 6% and 10% respectively.

Given that principal amount P = 5000

Number of years T = 3

Let R

_{1}= 8%,R

_{2}= 6% and R

_{3}= 10%

Total amount , …(i)

On substituting the known values in (i), we get

We know that, Compound interest ( CI) = total amount (A) - principal amount (P)

So, Compound interest ( CI) = 6296.4 - 5000 = 1296.4 Rupees

### What annual instalment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?

Let the principal amount P = 1092

It is given that T = 2, R = 12%

We have the formula for annual payment …(i)

On substituting the known values in (i), we get

So, 325 Rupees is the annual instalment.

### What annual instalment will discharge a debt of Rs 1092 due in 3 years at 12% simple interest?

Let the principal amount P = 1092

It is given that T = 2, R = 12%

We have the formula for annual payment …(i)

On substituting the known values in (i), we get

So, 325 Rupees is the annual instalment.

### What sum of money lent out at 6% for 2 years will produce the same interest as Rs. 1200 lent out at 5% for 3 years.

We calculate simple interest by the formula, …(i)

where P is Principal amount, T is number of years and R is rate of interest

Case Ⅰ

Let the sum of money = P

Here, we have

On substituting the values in (i), we get …(ii)

Case Ⅱ

Here, we have

On substituting the values in (i), we get …(iii)

It is given that the interest produced in both the cases is the same.

So, Equate (ii) and (iii)

On equating, we get

rupees.

Hence the sum of money P = 1500 Rupees

### What sum of money lent out at 6% for 2 years will produce the same interest as Rs. 1200 lent out at 5% for 3 years.

We calculate simple interest by the formula, …(i)

where P is Principal amount, T is number of years and R is rate of interest

Case Ⅰ

Let the sum of money = P

Here, we have

On substituting the values in (i), we get …(ii)

Case Ⅱ

Here, we have

On substituting the values in (i), we get …(iii)

It is given that the interest produced in both the cases is the same.

So, Equate (ii) and (iii)

On equating, we get

rupees.

Hence the sum of money P = 1500 Rupees

### What sum of money lent out at 5% for 3 years will produce the same interest as Rs. 900 lent out at 4% for 5 years.

We calculate simple interest by the formula, …(i)

where P is Principal amount, T is number of years and R is rate of interest

Case Ⅰ

Let the sum of money = P

Here, we have

On substituting the values in (i), we get …(ii)

Case Ⅱ

Here, we have

On substituting the values in (i), we get …(iii)

It is given that the interest produced in both the cases is the same.

So, Equate (ii) and (iii)

On equating, we get

rupees.

Hence the sum of money P = 1200 Rupees

### What sum of money lent out at 5% for 3 years will produce the same interest as Rs. 900 lent out at 4% for 5 years.

We calculate simple interest by the formula, …(i)

where P is Principal amount, T is number of years and R is rate of interest

Case Ⅰ

Let the sum of money = P

Here, we have

On substituting the values in (i), we get …(ii)

Case Ⅱ

Here, we have

On substituting the values in (i), we get …(iii)

It is given that the interest produced in both the cases is the same.

So, Equate (ii) and (iii)

On equating, we get

rupees.

Hence the sum of money P = 1200 Rupees

### Find the sum which will amount to Rs. 364.80 at 3 % per annum in 8 years at simple interest

Let the sum of money = P

We know the formula for total amount = A = P + SI

where A is the total amount, T is the principal amount and R is simple interest.

We know that

where P is Principal amount, T is number of years and R is rate of interest

So, …(i)

Here, we have

On substituting these values in (i), we get

On further simplifications, we get

Hence the sum of money P = Rs 285.

### Find the sum which will amount to Rs. 364.80 at 3 % per annum in 8 years at simple interest

Let the sum of money = P

We know the formula for total amount = A = P + SI

where A is the total amount, T is the principal amount and R is simple interest.

We know that

where P is Principal amount, T is number of years and R is rate of interest

So, …(i)

Here, we have

On substituting these values in (i), we get

On further simplifications, we get

Hence the sum of money P = Rs 285.

### The simple interest on a sum of money at the end of 3 years is of the sum itself. What rate percent was charged?

Let the sum of money = P

It is given that SI is times the sum itself = P.

We calculate simple interest by the formula,

where P is Principal amount, T is number of years and R is rate of interest

Here, we have

On substituting the known values we get,

On further simplifications, we have .

### The simple interest on a sum of money at the end of 3 years is of the sum itself. What rate percent was charged?

Let the sum of money = P

It is given that SI is times the sum itself = P.

We calculate simple interest by the formula,

where P is Principal amount, T is number of years and R is rate of interest

Here, we have

On substituting the known values we get,

On further simplifications, we have .

### A theatre company uses the revenue function dollars. The cost functions of the production . What ticket price is needed for the theatre to break even?

### A theatre company uses the revenue function dollars. The cost functions of the production . What ticket price is needed for the theatre to break even?

### Rewrite the equation as a system of equations, and then use a graph to solve.

A graph is a geometrical representation of an equation or an expression. It can be used to find solutions of equation.

We are asked to rewrite the equation as system of equations and graph them to solve it.

Step 1 of 3:

Equate each side of the equation to a new variable, y:

Here we get two points where both the graphs intersect each other. The points are (-8, 0) and (-3, -7.5). Thus, we can say that the solutions to the given set of equation are the points of intersection.

Note:

When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

### Rewrite the equation as a system of equations, and then use a graph to solve.

A graph is a geometrical representation of an equation or an expression. It can be used to find solutions of equation.

We are asked to rewrite the equation as system of equations and graph them to solve it.

Step 1 of 3:

Equate each side of the equation to a new variable, y:

Here we get two points where both the graphs intersect each other. The points are (-8, 0) and (-3, -7.5). Thus, we can say that the solutions to the given set of equation are the points of intersection.

Note:

When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

### Rewrite the equation as a system of equations, and then use a graph to solve.

Thus, the solutions are (0, 0) and (1, -14)

Step 3 of 3:

Plot the points and join them to get the respective graph.

Here, there is just one point where both the graphs intersect each other. The point is (4, -8). Thus, we can say that the point is the solution of the set of equation.

Note:

When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

### Rewrite the equation as a system of equations, and then use a graph to solve.

Thus, the solutions are (0, 0) and (1, -14)

Step 3 of 3:

Plot the points and join them to get the respective graph.

Here, there is just one point where both the graphs intersect each other. The point is (4, -8). Thus, we can say that the point is the solution of the set of equation.

Note:

When you graph a quadratic equation find three coordinate points to get the curve. But when it is a linear equation, just two points would give the path of the line.

### Find the simple interest on Rs. 6500 at 14% per annum for 73 days?

We calculate simple interest by the formula,

where P is Principal amount, T is number of years and R is rate of interest

Here, we have

On substituting the known values we get,

On further simplifications, we have rupees.

Thus, SI = 182 Rupees.

### Find the simple interest on Rs. 6500 at 14% per annum for 73 days?

We calculate simple interest by the formula,

where P is Principal amount, T is number of years and R is rate of interest

Here, we have

On substituting the known values we get,

On further simplifications, we have rupees.

Thus, SI = 182 Rupees.