Maths-

General

Easy

Question

# Find the y-intercept of the following function

f(x) = 2x^{2} – 4x – 6

Hint:

### For a quadratic function is in standard form, f(x)=ax2+bx+c.

The *y*-intercept is the point where a graph crosses the *y*-axis. In other words, it is the value of *y* when x=0.

## The correct answer is: -6.

### We have given a function

f(x) = 2x^{2} – 4x – 6

We will compare the given equation with the standard equation f(x)=ax^{2}+bx+c.

We know that for y intercept , x = 0

So, for finding y- intercept

f(x) = y = 2(0)^{2 }– 4(0) – 6

y = -6

On comparing with the standard form y-intercept is equal to c

y-intercept of given quadratic function is -6.

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