Maths
Grade-10
Easy

Question

For the square root function f left parenthesis x right parenthesis equals square root of x, the average rate of change between x = 1 & p is 0.366. What is the value of p?

  1. 2
  2. 3
  3. 4
  4. 5

hintHint:

average rate is a measure of how much the function changed per unit, on average, over that interval. It is derived from the slope of the straight line connecting the interval's endpoints on the function's graph. Substitute the given values and find value of p.

The correct answer is: 3


    Given , left parenthesis x right parenthesis equals square root of x, the average rate of change between x = 1 & p is 0.366
    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell f left parenthesis 1 right parenthesis equals square root of 1 equals 1 end cell row cell f left parenthesis p right parenthesis equals square root of p end cell end table
    A v e r a g e space r a t e equals fraction numerator f left parenthesis p right parenthesis minus f left parenthesis 1 right parenthesis over denominator p minus 1 end fraction
rightwards double arrow fraction numerator square root of p minus 1 over denominator p minus 1 end fraction equals 0.366 space left square bracket space u sin g space a squared minus b squared space equals space left parenthesis a plus b right parenthesis left parenthesis a minus b right parenthesis right square bracket
rightwards double arrow fraction numerator 1 over denominator square root of p plus 1 end fraction space equals space 0.366
square root of p space plus space 1 space equals space 2.732
square root of p space equals space 1.732
s u q a r i n g space o n space b o t h space s i d e space g i v e s space comma
p space equals space 3
    Therefore, the value of  p is 3.

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