Graph f(x) = 2x² + 4x + 3. What are axis of symmetry, vertex and y-intercept of the function

The correct answer is: 3

 
                                      

This quadratic function is in standard form, f(x)=ax²+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In f(x)=2x²+4x+3, a=2, b=4, and c=3. So, the equation for the axis of symmetry is given by
X = −(4)/2(2)
x = - 4/4
x = -1
The equation of the axis of symmetry for f(x)=2x²+4x+3 is x = -1.
The x coordinate of the vertex is the same:
h = -1
The y coordinate of the vertex is :
k = f(h)
k = 2(h)² + 4(h) + 3
k = 2(-1)² + 4(-1) + 3
k = 2 – 4 + 3
k = 1
Therefore, the vertex is (-1 , 1)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.
y = 2(0)² + 4(0) + 3
y = 0 + 0 + 3
y = 3
Therefore, Axis of symmetry is x = -1
Vertex is ( -1 , 1 )
Y- intercept is 3.