Graph f(x) = -3x² - 6x - 5. What are axis of symmetry, vertex and y-intercept of the function

The correct answer is: -5

                                   
This quadratic function is in standard form, f(x)=ax²+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In f(x)= =-3x² - 6x - 5, a= -3, b= -6, and c= -5. So, the equation for the axis of symmetry is given by
x = −(-6)/2(-3)
x = 6/-6
x = -1
The equation of the axis of symmetry for f(x)= = -3x² - 6x – 5 is x = -1.
The x coordinate of the vertex is the same:
h = -1
The y coordinate of the vertex is :
k = f(h)
k = -3(h)² - 6(h) - 5
k = -3(-1)² - 6(-1) - 5
k = -3 + 6 – 5
k = -2
Therefore, the vertex is (-1 , -2)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.
y = -3(0)² - 6(0) - 5
y = 0 + 0 - 5
y = -5
Therefore, Axis of symmetry is x = -1
Vertex is ( -1, -2)
Y- intercept is -5.