Maths-
General
Easy

Question

Graph the function f(x)= -3x2 +12x+5

hintHint:

For a quadratic function is in standard form, f(x)=ax2+bx+c.
A vertical line passing through the vertex is called the axis of symmetry for the parabola.
Axis of symmetry x=−b/2a
Vertex The vertex of the parabola is located at a pair of coordinates which we will call (h, k). where h is value of x in axis of symmetry formula and k is f(h).

The correct answer is: (2 , 17)


    We have given a function
    f(x)= -3x2+12x+5
    We have to draw graph of given function,
    For drawing graph we will need to find some points on curves
    Firstly we will find vertex of the function,
    x = -b/2a
    = -(12)/2(-3)
    = -12 / -6
    = 2
    The x coordinate of the vertex is the same:
    h = 2
    The y coordinate of the vertex is :
    k = f(h)
    k = -3h2 + 12h + 5
    k = -3(2)2 + 12(2) + 5
    k = -12 + 24 + 5
    k = 17
    Therefore, the vertex is (2 , 17)
    Select a few x values, and plug them into the equation to find the corresponding y values. The x values should be selected around the vertex.

    x

    y

    0

    5

    1

    14

    2

    17

    3

    14

    4

    5

    Plot the obtained points and draw the graph

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