Maths-
General
Easy
Question
Graph the function f(x)= 3x2-6x+2
Hint:
For a quadratic function is in standard form, f(x)=ax2+bx+c.
A vertical line passing through the vertex is called the axis of symmetry for the parabola.
Axis of symmetry x=−b/2a
Vertex The vertex of the parabola is located at a pair of coordinates which we will call (h, k). where h is value of x in axis of symmetry formula and k is f(h).
The correct answer is: (1 , -1)
We have given a function
f(x)= 3x2-6x+2
We have to draw graph of given function,
For drawing graph we will need to find some points on curves
Firstly we will find vertex of the function,
x = -b/2a
= -(-6)/2(3)
= 6 / 6
= 1
The x coordinate of the vertex is the same:
h = 1
The y coordinate of the vertex is :
k = f(h)
k = 3h2 - 6h + 2
k = 3(1)2 - 6(1) + 2
k = 3 - 6 + 2
k = -1
Therefore, the vertex is (1 , -1)
Select a few x values, and plug them into the equation to find the corresponding y values. The x values should be selected around the vertex.
x
y
-1
11
0
2
1
-1
2
2
3
11
Plot the obtained points and draw the graph
x
y
-1
11
0
2
1
-1
2
2
3
11
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