Maths-
General
Easy
Question
Identify the y – intercept , axis of symmetry , and vertex of the graph of each function . G(x)= -x2+4x+5
Hint:
For a quadratic function is in standard form, f(x)=ax2+bx+c.
A vertical line passing through the vertex is called the axis of symmetry for the parabola.
Axis of symmetry x=−b/2a
Vertex The vertex of the parabola is located at a pair of coordinates which we will call (h, k). where h is value of x in axis of symmetry formula and k is f(h).
The y-intercept is the point where a graph crosses the y-axis. In other words, it is the value of y when x=0.
The correct answer is: ( 2 , 9 )
This quadratic function is in standard form, f(x)=ax2+bx+c.
For every quadratic function in standard form the axis of symmetry is given by the formula x=−b/2a.
In g(x)= -x2+4x+5, a= -1, b=4, and c=5. So, the equation for the axis of symmetry is given by
x = −(4)/2(-1)
x = - 4/-2
x = 2
The equation of the axis of symmetry for g(x)=-x2+4x+5 is x = 2.
The x coordinate of the vertex is the same:
h = 2
The y coordinate of the vertex is :
k = g(h)
k = -(h)2 + 4(h) + 5
k = -(2)2 + 4(2) + 5
k = -4 + 8 + 5
k = 9
Therefore, the vertex is (2 , 9)
For finding the y- intercept we firstly rewrite the equation by substituting 0 for x.
y = -(0)2 + 4(0) + 5
y = 0 + 0 + 5
y = 5
Therefore, Axis of symmetry is x = 2
Vertex is ( 2 , 9 )
Y- intercept is 5.
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