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Question

I f blank f to the power of 1 end exponent open parentheses 0 close parentheses equals 3 blank t h e n blank stack lim with x rightwards arrow 0 below invisible function application fraction numerator x to the power of 2 end exponent over denominator f open parentheses x to the power of 2 end exponent close parentheses minus 6. f open parentheses 4 x to the power of 2 end exponent close parentheses plus 5. f open parentheses 7 x to the power of 2 end exponent close parentheses end fraction equals

  1. 1/36    
  2. -1/36    
  3. 1/34    
  4. 1/106    

The correct answer is: 1/36


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