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Maths-

General

Easy

Question

If $open vertical bar table row cell lambda to the power of 2 end exponent plus 3 lambda end cell cell lambda minus 1 end cell cell lambda plus 3 end cell row cell lambda plus 1 end cell cell 2 minus lambda end cell cell lambda minus 4 end cell row cell lambda minus 3 end cell cell lambda plus 4 end cell cell 3 lambda end cell end table close vertical bar comma$ the value of t is

16
18
17
19

The correct answer is: 18

Since it is an identity in $open vertical bar table row cell a left parenthesis 1 plus w right parenthesis end cell cell b w to the power of 2 end exponent end cell cell a w end cell row cell b left parenthesis w plus w to the power of 2 end exponent right parenthesis end cell c cell b w to the power of 2 end exponent end cell row cell c left parenthesis w to the power of 2 end exponent plus 1 right parenthesis end cell cell a w end cell c end table close vertical bar$ so satisfied by every value of $lambda$ . Now put $B C equals left square bracket negative b minus a right square bracket open square brackets table row cell a end cell row cell negative a end cell end table close square brackets equals left square bracket a to the power of 2 end exponent minus a b right square bracket$ in the given equation, we have $t equals open vertical bar table row 0 cell negative 1 end cell 3 row 1 2 cell negative 4 end cell row cell negative 3 end cell 4 0 end table close vertical bar equals negative 12 plus 30 equals 18$

Related Questions to study

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parallel

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