Maths-
General
Easy
Question
If then sin (A-B) =
Hint:
to find the value of the given equation we will use the formula Sin (A - B) = (Sin A * Cos B) - (Cos A * Sin B) and simplify the equation then using the given equations we will find the value of the required equations using the trigonometric identities.
The correct answer is:
GIVEN-
√2 cos A = cos B + cos3 B..... equation 1
∴ cos A = 1/√2 (cos B + cos3 B) ........ (Dividing both sides by √2)
√2 sin A = sin B - sin3 B..... equation 2
∴ sin A = 1/√2 (sin B - sin3 B) ........ (Dividing both sides by √2)
TO FIND-
Sin (A - B)
SOLUTION-
We know that-
Sin (A - B) = (Sin A * Cos B) - (Cos A * Sin B)
∴ Sin (A - B) = [1/√2 (sin B - sin3 B) * cos B] - [1/√2 (cos B + cos3 B) * sin B] ...... (From Equations i & ii)
∴ Sin (A - B) = [1/√2 * (sin B Cos B - sin3 B Cos B)] - [1/√2 * (sin B cos B + cos3 B * sin B)]
∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin3 B Cos B - (1/√2 sin B cos B + 1/√2 cos3 B * sin B)
∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin3 B Cos B - 1/√2 sin B cos B - 1/√2 cos3 B * sin B
∴ Sin (A - B) = 1/√2 sin B Cos B - 1/√2 sin3 B Cos B - 1/√2 sin B cos B - 1/√2 cos3 B * sin B
∴ Sin (A - B) = -1/√2 sin3 B Cos B - 1/√2 cos3 B * sin B
∴ Sin (A - B) = -1/√2 sin B Cos B (sin2 B +cos2 B)
= -1/2√2 sin2B
Now squaring and adding equation 1 and 2 we get
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