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Maths-

General

Easy

Question

In the following figure, AB is parallel to CD , then the value of x in degrees is

90°
100°
60°
20°

hint Hint:

In this question, we have to find the value of the x from the figure. For this, first we will draw a line parallel to the parallel lines given and passing through the intersecting point of the transversal where the angle is formed. Later using the angle properties of the parallel lines we will find the value of x.

The correct answer is: 90°

Drawing a line EF parallel to AB and CD passing through O the angle (x+10) $degree$
As ABIIEF and EFIICD with tangent intersecting at O
So, $angle$ FOD = $angle$ CDO = 30 $degree$ [alternate interior angle ]
Also, $angle$ BOF + $angle$ OAB = 180 $degree$ [interior opposite angle ]
$rightwards double arrow$ ((x+10)+30) $degree$ +110 $degree$ =180 $degree$
$rightwards double arrow$ x=90 $degree$

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